An equilateral triangle has 3 equal sides by definition.
so we know that x+2 = -2x+20 because we're told that those are both lengths of the triangle's sides. let's solve for x.
x+2 = -2x + 20
add 2x to both sides.
3x + 2 = 20
subtract 2 from both sides.
3x = 18
divide both sides by 3.
x = 6
now, let's find the length of the sides. plug 6 into one side, which is x+2.
6+2 = 8. so each side's length must be equal to 8. let's just check to make sure we didn't make a mistake. if this is correct, then -2x + 20 should also = 8.
-2(6) + 20
-12 + 20
8.
so we know that the sides = 8. let's see if 14 - x or 2x+4 are equal to 8 when we plug in 6 for x.
14 - 6 = 8. so 14-x could be a length for a side.
2(6) + 4 = 12 + 4 = 16. so 2x + 4 can not be a length for a side.
the answer is 14 - x only, or C.
An easy way to do this is to do trial and error.
All possible places to put the bracket:
a) (25 - 8) - 2 = 19 But since BEDMAS goes from left to right with Addition and Subtraction, the equation is unaffected.
b) 25 - (8 - 2) = 19
25 - 6 = 19
Therefore b) is correct.
The intercepts of the given equations is as given in the task content is; Choice B; (15,0,0),(0,10,0) ,(0,0,5).
<h3>What are the intercepts of the equation as give in the task content?</h3>
The x-intercept of the given equation can be determined by setting values of y and z to zero.
The y-intercept can be determined by setting x and z to zero.
While the z-intercept can be determined by setting x and y to zero.
Consequently, the X-intercept of the given equations is; 2x +3(0) = 30; x = 15.
Therefore, we have; (15,0,0)
The y-intercept is therefore; 2(0) +3y = 30; 3y = 30; y = 30/3 = 10 and. we have; (0,15,0)
And hence, the z-intercept is; z = 30/6 = 5.
Read more on intercept;
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the complete question in the attached figure
Volume of the sand V=(1/3)*h*π*r²
we have that
h=30 mm
r=10 mm
v=(1/3)*30*π*10²=1000≈3140 mm³
the rate is 50 mm³/seg
50 mm³--------------------------------------> 1 seg
3140 mm³-------------------------------- X
x=3140/50=62.8 seg
the answer is 62.8 seg
