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Naddik [55]
3 years ago
12

What biomes receive less then 100 Cm of rain each year? Check all that apply

Biology
1 answer:
jeyben [28]3 years ago
7 0

<u>Answer</u>:- <em>Option 3 </em>(desert), <em>Option 4</em> (tundra) and <em>Option 5</em> (grassland).

<u>Explanation</u>:-

The amount of rainfall varies in different biomes:-

1. Tropical rain forests - The annual rainfall in these forests falls in the range of <em>125 to 660 cm</em> which varies according to the seasons.

2. Temperate rain forest - The annual rainfall in these forests can range from <em>200 cm to 350 cm</em> depending on the region where they are found. The annual rainfall is higher in warmer regions .

3. Desert - As the name suggests, the desert areas do not get enough rainfall. The annual rainfall in a desert is less than <em>25 cm</em>.

4. Tundra - It is a biome which is found in relatively cooler climates and the amount of rainfall is very less these regions. The annual rainfall in tundra biomes is less than <em>20 cm</em>.

5. Grassland - in these biomes, the rainfall is higher than the tundra and desert but is not as high as the rain forests and thus, grass is the dominant vegetation. The annual rainfall ranges from <em>60-90 cm</em>.

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If a mutation occurred in SODD that prohibited its interaction with the DD of TNF receptor, the TNF receptor would
Xelga [282]

Answer: If a mutation occurred in Silencer of Death Domain (SODD) that prohibited its interaction with the DD of TNF receptor, the TNF receptor would evoke its response by binding to a transmembrane receptor, TNFR1.

Explanation: Binding to TNFR1 inhibits the recruitment of cytoplasmic signaling proteins to TNFR1 to prevent recruitment of a number of protein (TRADD) or prevent spontaneous aggregation of the cytoplasmic death domains of TNFR1 molecules.

SODD mechanism is useful in preventing unwarranted TNFR1 activation in the process of apoptosis.

3 0
3 years ago
The dna content for an organism is analyzed. The results showed that 21% of the nucleotides contained the nitrogenous base adeni
Serjik [45]

If the results show that 21% of the nucleotides contain adenine, then the cytosine fraction in vivo is 29% and the thymine fraction is also 21% (options A and C).

<h3>Define double helix model of DNA?</h3>
  1. DNA is a double helix molecule made up of two long strands of nucleotides.
  2. There are four types of nucleotides in DNA, each containing a different nitrogenous base: adenine, guanine, thymine, cytosine.
  3. Adenine always pairs with thymine and guanine pairs with cytosine, according to the base-pairing rules.
  4. As a result, the percentage of adenine equals the percentage of thymine, and the remaining percentage equals guanine + cytosine (29 + 29 = 58 >> 58 + 21 + 21 = 100).
  5. Therefore, if the results show that 21% of the nucleotides contain adenine, then the percentage of cytosine in vivo is 29% and the percentage of thymine is also 21%

To know more about double helix model of DNA, visit:

brainly.com/question/3789581

#SPJ4

The complete question is as follows:

The DNA content for an organism is analyzed. The results showed that 21% of the nucleotides contained the nitrogenous base adenine. What else can be inferred based on this data? Select all that apply

A) The percentage of cytosine is 29%.

B) The percentage of adenine is 21% for all organisms.

C) The percentage of thymine in the organism is also 21%.

D) The percentage of guanine in the organism is also 21%.

E) The percentage for cytosine in the organism is also 21%.

4 0
9 months ago
Which muscle is the longest and thinnest in the body?
SpyIntel [72]

Answer:

Sartorius and Stapedius muscle

Explanation:

Sartorius is the longest and stapedius is the thinnest

5 0
3 years ago
If a substance has a density of 2.5 g/ml and the volume of the substance is 8 ml what is the mass of the substance
dezoksy [38]
The answer will be 20 grams
7 0
3 years ago
Considering the Mendelian traits tall (D) versus dwarf (d) and violet (W) versus white (w), consider the crosses below and deter
Artyom0805 [142]

Answer:

DDWw x Ddww

DdWw x DDww

DDWw x DDww

Explanation:

D for tallness

d for dwarfness

W for violet

w for  white

For Parental Plants that has

tall, violet x tall, white

 The representation will be

DDWW × DDww      (We the apply the mendelian crossing)

This will yield offsprings with the following trait

DDDD × DwDw

DDDD × DwDw

DWDW x WwWw

DdWw x ddww

Ddww x ddWw

DdWw x DdWw

DDWw x ddww

From the above Offsprings

1/2 tall, white and 1/2 tall, violets offspring are

DDWw x Ddww

DdWw x DDww

DDWw x DDww

7 0
3 years ago
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