Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
B is the answer b.converse
Answer:
y = -(3/7)x + 2
Step-by-step explanation:
(see attached)
recall that the slope-intercept form of a linear equation is
y = mx + b
where m = slope = given as -(3/7)
and b = y-intercept = 2
substituting these values into the eqation:
y = mx + b
y = -(3/7)x + 2