3 years ago

Jerry is 6 years older than his brother drew the sum of their ages is 30 how old are they

1 answer:

8 0

Jerry's brother is x years old
Jerry is X + 6 years old
x + x + 6 = 30
2x+6=30
2x+6-6=30-6
2x=24
2x/2=24/2
x=12 Jerry's brother age
X+6= 18 Jerry age

You might be interested in

Help me answer this geometry question please!! will give brainliest and 5 stars!!

Zinaida [17]

B . using SAS theorem

5 0

3 years ago

I NEED HELP WITH 2 QUESTIONSS

ryzh [129]

1. 75

2. Between 87 and 88

6 0

2 years ago

A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

4 0

3 years ago

Read 2 more answers

Please anwser

Black_prince [1.1K]

The answers are
M1 = 112°
M2 = 26°

6 0

3 years ago

Rewrite expression as a single power<img src="https://tex.z-dn.net/?f=6%5E%7B4%7D%2A%206%5E%7B4%7D" id="TexFormula1" title="6^{4

victus00 [196]

Answer:

6^8

Step-by-step explanation:

6^4 * 6^4

We know that a^b * a^c = a^( b+c)

6^(4+4)

6^8

5 0

3 years ago

Read 2 more answers