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3 years ago

Find the product. 9 · (-8) =

Mathematics

2 answers:

navik [9.2K]3 years ago

7 0

Answer: -72

Explanation; in order to be able to get the answer you should remove the brackets by multiplying 9 and -8 to get -72.

Drupady [299]3 years ago

5 0

Answer:

Step-by-step explanation: 6

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Of the four choices given, which two, when written as a system, have a solution of (–4, 5)?

Alex787 [66]

Answer:

f(x)= 1.8x + 1

Step-by-step explanation:

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3 years ago

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Which number is a factor of 15 but not a multiple of 3

tester [92]

Is 5 because the factor of 15 can not be other number except 5

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4 years ago

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Describe how the placement of the decimal point changes when you multiply a number by the power of ten. How is this the same and

Solnce55 [7]

Answer: the answer to your question is

Recall that when you multiply a decimal by a power of ten (10, 100, 1,000, etc), the placement of the decimal point in the product will move to the right according to the number of zeros in the power of ten. For instance, 4.12 · 10 = 41.2.

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3 years ago

Please help me with this math question.

zmey [24]

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6 0

3 years ago

The reported average cost per workbook at a large college is $27.50. A professor claims that the actual average cost per workboo

nadezda [96]

Answer:

We conclude that the actual average cost per workbook is higher than $27.50.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $27.50

Sample mean, $\bar{x}$ = $28.90

Sample size, n = 44

Alpha, α = 0.05

Population standard deviation, σ = $5.00

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 27.50\text{ dollars}\\H_A: \mu > 27.50\text{ dollars}$

We use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{28.90 - 27.50}{\frac{5.00}{\sqrt{44}} } = 1.8573$

Now, $z_{critical} \text{ at 0.05 level of significance } = 1.64$

Since,

$z_{stat} > z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis.

Thus, we conclude that the actual average cost per workbook is higher than $27.50.

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4 years ago