Answer:
(m º n)(x) = x -2
Step-by-step explanation:
Here, in the given expression:
m(x)= x+1 and n(x) = x - 3
To find : (m º n)(x)
Now, solving for (m º n)(x)
(m º n)(x) = m (n (x)) = m (x-3)
also, m (x-3) = (x -3) + 1 = x -2
So, (m º n)(x) = x -2
Answer:
Lamda= 4 students/min, µ= 5 students/min
P= Lamda/µ= 4/5= 0.8
a.) Probability that system is empty= P0= 1-P= 1-0.8= 0.2
b.) Probability of more than 2 students in the system= ∑(n=3 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2)= (.2)*(5- - .2 - (.8)*.2 – (.2)*.8^2))= 0.848
Probability of more than 3 students in the system= ∑(n=4 to inf) P^n*P0= (1-P)*(1/(1-P) – (1-P) –(1-P)*P –(1-P)*P^2 – (1-P)*P^3)= 0.768
c.) W(q)= Waiting time in Queue= lamda/µ(µ- lamda)= 4/5(1)= 0.8 minutes
d.) L(q)= lamda*W(q)= 4*.8= 3.2 students
e.) L(System)= lamda/(µ-lamda)= 4 students.
f.) If another server with same efficiency as the 1st one is added, then µ= 6 sec/student= 10 students/min.
P= 4/10= 0.4
Probability that system is empty= P0= 1-.4= 0.6
W(q)= 4/10(10-4)= 0.0667 minutes
L(q)= Lamda*W(q)= 4*.0667=0.2668
L(system)= Lamda/(µ-lamda)= 4/6= .667
Step-by-step explanation:
Answer:
0, 1/13, 49/100, 1/2, 11/20, 8/9, 1
Step-by-step explanation:
You know the smallest is 0, largest is 1
the middle is 1/2
49/100 is slightly smaller than 1/2 or 50/100
11/20 is slightly larger than 1/2 or 10/20
1/13 is slightly larger than 0
8/9 is slightly smaller than 1
please give thanks :)
and brainliest :)
