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Pani-rosa [81]
3 years ago
5

Find the LCM and HCF of 64 and 72 using prime factors​

Mathematics
2 answers:
Harrizon [31]3 years ago
5 0

Answer:

8x8 and 8x9

Step-by-step explanation:

because 8x8 is 64 and 8x9 is 72

Nadya [2.5K]3 years ago
4 0

What is the LCM of 64 and 72?

Find the prime factorization of 64.

Find the prime factorization of 72. 72 = 2 × 2 × 2 × 3 × 3.

Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM: LCM = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3.

LCM = 576.

What is the GCF of 64 and 72?

Find the prime factorization of 64. 64 = 2 × 2 × 2 × 2 × 2 × 2.

Find the prime factorization of 72. 72 = 2 × 2 × 2 × 3 × 3.

To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 2 × 2 × 2.

GCF = 8.

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Learning Task 3: In your answer sheet, write the letter of the correct answe
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Answer:

a.) May or may not a polynomial function ( depends on c)

b.) Not a polynomial function.

c.) Not a polynomial function.

d.) It is a polynomial function.

Step-by-step explanation:

A polynomial function is of the form - a_{n}x^{n} + a_{n-1} x^{n-1} + a_{n-2} x^{n-2} + .....+ a_{1}x + a_{0}

where n is positive integer and n\neq 0

a.)

P(x) = 2x³ + 32 - 4x + 4c

It may or may not a polynomial function because we did not know about the constant c.

b.)

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8 0
3 years ago
Some college graduates employed full-time work more than hours per week, and some work fewer than hours per week. We suspect tha
Alex_Xolod [135]

Answer:

a)Null hypothesis:\mu =40      

Alternative hypothesis:\mu \neq 40      

b) A Type of error I is reject the hypothesis that \mu is equal to 40 when is fact \mu is equal to 40c) We can commit a Type II Error, since by definition "A type II error is the non-rejection of a false null hypothesis and is known as "false negative" conclusion"Step-by-step explanation:Assuming this problem: "Some college graduates employed full-time work more than 40 hours per week, and some work fewer than 40 hours per week. We suspect that the mean number of hours worked per week by college graduates, [tex]\mu , is different from 40 hours and wish to do a statistical test. We select a random sample of college graduates employed full-time and find that the mean of the sample is 43 hours and that the standard deviation is 4 hours. Based on this information, answer the questions below"

Data given

\bar X=43 represent the sample mean

\mu population mean (variable of interest)

s=4 represent the sample standard deviation

n represent the sample size  

Part a: System of hypothesis

We need to conduct a hypothesis in order to determine if actual mean is different from 40 , the system of hypothesis would be:    

Null hypothesis:\mu =40      

Alternative hypothesis:\mu \neq 40      

Part b

In th context of this tes, what is a Type I error?

A Type of error I is reject the hypothesis that \mu is equal to 40 when is fact [tex]\mu is equal to 40

Part c

Suppose that we decide not to reject the null hypothesis. What sort of error might we be making.

We can commit a Type II Error, since by definition "A type II error is the non-rejection of a false null hypothesis and is known as "false negative" conclusion"

5 0
3 years ago
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