No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be

or

so
if w^2-9w+81 is perfect square, factored form is either

or

aka

or
expand them
(x+9)^2=x^2+18x+81, wron middle term
(x-9)^2=x^2-18x+81 wrong
so it is not
Answer:
(a + b -c) x (x +y )
Step-by-step explanation:
Firstly, factor out x from the expression
Then, factor out the y from the expression
This should be your answer
The answer should not depend on which machine or which pencil you use to
find it. If you work a problem two different ways and get two different answers,
then at least one of them is wrong, and there's a pretty good chance that both
of them are.
(9.99 of anything) + (1.11 of the same thing) = 11.1 of them
9.99 (x 10^-2) + 1.11 (x 10^-2) = <em>11.1 (x 10^-2)</em> .
Can we do any more with that ?
10^-2 = 1 / 10^2 = 1 / 100 .
11.1 x 10^-2 = 11.1 / 100 = <em>0.111</em>