Answer:
Range = {-1, 1, 3}
Step-by-step explanation:
<u><em>The question asks for the range.</em></u>
The function given is
The domain is the set of 3 numbers:
Domain = {4,6,8}
We need to find the range.
First, the range is the set of all y-values for which the function is defined.
When we will be given the domain with a set of numbers, the range would be the numbers that we get when we evaluate the the function at those numbers.
So, we evaluate the function (y-values) at x = 4,6, and 8.
At x = 4:
At x = 6:
At x = 8:
Thus, the range is:
Range = {-1, 1, 3}
Answer:
I think its 336. I might be wrong though, But I hope I am right.
Step-by-step explanation:
Answer:
We know that the equation of the circle in standard form is equal to <em>(x-h)² + (y-k)² = r²</em> where (h,k) is the center of the circle and r is the radius of the circle.
We have x² + y² + 8x + 22y + 37 = 0, let's get to the standard form :
1 - We first group terms with the same variable :
(x²+8x) + (y²+22y) + 37 = 0
2 - We then move the constant to the opposite side of the equation (don't forget to change the sign !)
(x²+8x) + (y²+22y) = - 37
3 - Do you recall the quadratic identities ? (a+b)² = a² + 2ab + b². Now that's what we are trying to find. We call this process <u><em>"completing the square"</em></u>.
x²+8x = (x²+8x + 4²) - 4² = (x+4)² - 4²
y²+22y = (y²+22y+11²)-11² = (y+11)²-11²
4 - We plug the new values inside our equation :
(x+4)² - 4² + (y+22)² - 11² = -37
(x+4)² + (y+22)² = -37+4²+11²
(x+4)²+(y+22)² = 100
5 - We re-write in standard form :
(x-(-4)²)² + (y - (-22))² = 10²
And now it is easy to identify h and k, h = -4 and k = - 22 and the radius r equal 10. You can now complete the sentence :)
