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pantera1 [17]
4 years ago
5

2. Xamdi is having a birthday party. The event location says the total cost includes a fixed rental fee of $80 and $10 per guest

.
(a) Using x to represent the number of guests, write an expression that describes the total cost of the party.
(b) Find the total cost if Xamdi has 9 guests attending the party.


25 POINTS
Mathematics
1 answer:
Stells [14]4 years ago
4 0
80+10x is the expression. To find the cost for 9 guests, simply plug in 9 for x. This becomes an equation reading 80+10(9)=170. The total cost for 9 guests is $170.00.


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The answer would be B it would be parallel to the graph of 12y = 2x + 3
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Prove the divisibility of the following numbers:<br><br> 51^7-51^6 by 25
vampirchik [111]

To prove the divisibility lets expand each number first to get the complete picture of the problem

51^7 =   8.974106779 . 10^11

51^6 =  1.75962878 . 10^10

(51^7 - 51^6) =  8.974106779 . 10^11 -  1.75962878 . 10^10

                    = 8.798143901. 10^11

\frac{8.798143901. 10^11}{25}

= 3.51925756. 10^10

That is the answer expressed in scientific notation

= 35192575600

Which means the divisibility is proven

8 0
3 years ago
Read 2 more answers
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seventeen million, eight hundred seventy-four thousand

Step-by-step explanation:

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6 0
1 year ago
What is 0.00000004 as a power of 10?
MrRissso [65]

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8 0
4 years ago
A circular cylindrical container, open at the top, and having a capacity of 24pi cubic inches, is to be manufactured. If the cos
otez555 [7]

Answer: radius r = 2 inches

height h = 6 inches

Step-by-step explanation:

Given;

Volume V = 24πin3

Volume of a cylinder is given by

V = πr^2h

h = V/πr^2. ....1

Where, h = height and r = radius of cylinder

For the surface area of the cylinder with open top. we have,

S = 2πrh + πr^2

For the cost of materials used, let k represent the cost of materials used for the body of the cylinder.

Then, for the bottom will be 3k

Total cost will be represented by C, which gives

C = 2πrhk + 3πr^2k. .....2

Substituting eqn 1 to 2, we have;

C = 2πrVk/πr^2 + 3πr^2k

C = 2Vk/r + 3πr^2k

The material cost is minimum at dC/dr = 0

dC/dr = -2Vk/r^2 + 6πrk =0

6πrk = 2Vk/r^2

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r = (2×24π/6π)^-3

r = (8)^-3

r = 2

Substituting r = 2 into eqn1

h = 24π/π(2^2)

h = 24/4 = 6

h = 6

5 0
4 years ago
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