E=mc^2 in terms of m

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

3 years ago

Graph the line with 1/2 slope passing through the point (-5,1).

Ghella [55]

Answer:

Go on dezmos it will do it for you if you just wright the coordinates in

Step-by-step explanation:

5 0

3 years ago

State the solution to the equations f(x) and g(x).

Digiron [165]

Answer:

x = -1

Step-by-step explanation:

f(x) = g(x) when x = -1

3 0

2 years ago

Read 2 more answers

{ x - 3y= -3 & x + y= 5 We are to use the graph to solve the given system of equations, then enter your solution below. I ge

nasty-shy [4]

Answer:

Solution: (3, 2)

Step-by-step explanation:

It's easier to graph when the equation of the lines are in their slope-intercept form, y = mx + b.

x - 3y = -3

-3y = -x - 3

Divide both sides by -3:

$\frac{-3y}{-3} = \frac{-x - 3}{-3}$

y = 1/3x + 1

where slope = 1/3

y-intercept = 1

x + y = 5

Subtract x from both sides to isolate y:

x - x + y = - x + 5

y = -x + 5

where slope = -1

y-intercept, 5

I started by graphing the y-intercepts of each line. Then, I used the slope of each linear equation (rise over run) to plot the next points on the graph. In the attached screenshot of the graph, x - 3y = -3 is the blue line, while x + y = 5 is the green line. Their intersection occurs at point, (3, 2).

Therefore, the solution is (3, 2).

Please mark my answers as the Brainliest if you find my explanations helpful :)

5 0

3 years ago

One way to compute a 15% tip for a bill is to multiply the bill by 0.15. A restaurant bill was $42.40. Calculate the tip. Enter

Andreyy89

Answer:6.36

Step-by-step explanation:

Multiply the bill($42.40) by 0.15

8 0

2 years ago