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Gemiola [76]
2 years ago
14

4.6w - 3 + 6.4x - 1.9y

Mathematics
2 answers:
torisob [31]2 years ago
7 0

Answer:

What do you want me to do? Its already simplified to its lowest terms

sasho [114]2 years ago
4 0

Answer:

w = 0.652173913 + -1.391304348x + 0.4130434783y

Step-by-step explanation:

I am pretty sure this is it.

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I REALLY NEED HELP, ILL MEDAL!!!!
lara31 [8.8K]
Well, first of all, the first statement  (ABC = ADC) looks like it just says
that the two halves of the little square ... each side of the diagonal ...
are congruent.  That's no big deal, and it's no help in answering the
question.

The effect of the dilation is that all the DIMENSIONS of the square
are doubled ... each side of the square becomes twice as long.

Then, when you multiply (length x width) to get the area, you'd have

           Area = (2 x original length) x (2 x original width)

and that's
the same as      (2 x 2) x (original length x original width)

                        =     (4)  x  (original area) .


Here's an easy, useful factoid to memorize:

-- Dilate a line (1 dimension) by 'x' times . . . multiply the length by  x¹

-- Dilate a shape (2 dimensions) by 'x' . . . multiply area by  x²

-- Dilate a solid (3 dimensions) by 'x' . . . multiply volume by  x³

And that's all the dimensions we have in our world.
_______________________________

Oh, BTW . . .

-- Dilate a point (0 dimensions) by 'x' . . . multiply it by  x⁰  (1)

5 0
3 years ago
Someone help I don't know what the diameter or radius is​
Elenna [48]
<h3><u>Answer:</u></h3>

52.38 inch² & 261.90 inch²

<h3><u>Step-by-step explanation:</u></h3>

Here we need to find the area of the sector . So according to formula we know the area of sector as ,

\boxed {\sf Area_{(sector)}= \dfrac{\theta}{360}\times \pi r^2 }

Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,

=> Area = ∅/ 360° × π r²

=> Area = 60°/360° × 22/7 × (10in.)²

=> Area = 1/6 * 22/7 * 100 in²

=> Area = 52 .380 in²

<h3><u>★</u><u> </u><u>Hence </u><u>the </u><u>area </u><u>o</u><u>f </u><u>the </u><u>red</u><u> </u><u>sector </u><u>is </u><u>5</u><u>2</u><u>.</u><u>3</u><u>8</u><u> </u><u>inch²</u><u>.</u></h3>

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

Now let's find out the area of blue sector .The angle subtended by the arc will be (360-60)°=300° .

=> Area = 300/360 × 22/7 × 100 in²

=> Area = 261. 90 in²

<h3><u>★</u><u> </u><u>H</u><u>ence </u><u>the </u><u>area </u><u>of </u><u>blue </u><u>sector </u><u>is </u><u>2</u><u>6</u><u>1</u><u>.</u><u>9</u><u>0</u><u> </u><u>inch</u><u>²</u><u>.</u></h3>

\boxed{\red{\sf Area _{(red \ sector )} = 52.38 in^2 }}

\boxed{\blue{\sf Area _{(blue \ sector )} = 261.90 in^2 }}

5 0
3 years ago
Plz help me i dont understand
wolverine [178]

your answer is 52. just subtract: 72-20=52

6 0
3 years ago
Read 2 more answers
Solve the following problem: An investor earned triple the profits of what she earned last year. If she made $500,000.48 total f
myrzilka [38]

Answer:

$125,000.12 last year

$375,000.36 this year

Step-by-step explanation:

Last year, her profits were x.

This year, the profits are three times greater, so they are 3x.

Altogether for both years, the profits are x + 3x = 4x.

The profits for both years combined are $500,000.48

4x = 500,000.48

Divide both sides by 4.

x = 500,000.48/4

x = 125,000.12

The profits last year were $125,000.12

This year, the profits were 3x = 3(125,000.12) = 375,000.36, or $375,000.36

7 0
3 years ago
Jessie sorted the coins in her bank. She made 7 stackes of 6 dimes and 8 sacks of 5 nickels. She then found 1 dime and 1 nickle.
Bess [88]

Answer:

43 dimes = $4.30 41 nickels =$1.96. hope this helps

Step-by-step explanation:

6x7= 42

42+2=43

43x10=430

8x5=40

40+1=41

41x5=196

8 0
3 years ago
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