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3 years ago

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An account earns simple interest. $300 at 4% for 3 years a. Find the interest earned. $ b. Find the balance of the account. $

2 answers:

aliina [53]3 years ago

5 0

A. take 300*0.04*3 which is $36

b. add $36 to $300

Oksi-84 [34.3K]3 years ago

5 0

Answer:

a. $36

b. $336

Step-by-step explanation:

The simple interest on a amount is:

A=P(1+rt)

A is the amount after interest, P is the amount before interest, r is the rate of interest and t is the time in years.

a.

We can use the formula:

$=300\cdot{(1+0.04\cdot{3})}=300\cdot{1.12}=336$

The interest earned is the amount after interest minus the original amount before interest:

$=336-300=36$

$36 of interest was earned

b.

The balance of the account is $336 worked out in a

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NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

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The angle $\theta$ is calculated as thus:

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For a vector

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$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

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2 years ago

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100 + 8d = 300; d = 25; The kitten will triple its weight in 25 days

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3 years ago

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Step-by-step explanation:

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3 years ago

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Nesterboy [21]

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3 years ago

Helppop!!A car and van are driving on a highway. The table shows the amount y (in gallons) of gas in the cars gas tank after dri

Korvikt [17]

Answer:

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Step-by-step explanation:

Given

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From the table, we have:

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So, we have:

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By comparison to: $y = mx + b$

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This implies that for every mile traveled, the van uses 1/5 gallon of gas.

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We have:

$y = -\frac{1}{5}x + 31$ --- The van

$y = -\frac{1}{40}x + 15$ --- The car

Equate both

$-\frac{1}{5}x + 31 =-\frac{1}{40}x + 15$

Collect like terms

$\frac{1}{40}x -\frac{1}{5}x =-31 + 15$

$\frac{1}{40}x -\frac{1}{5}x =-16$

Take LCM

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$\frac{- 7x}{40} = -16$

Solve for -7x

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Solve for x

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5 0

3 years ago