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vichka [17]
3 years ago
15

Certain items are purchased jointly. If each person pays 8coins, the surplus is 3coins, and if each person gives 7coins, the def

iciency is 4coins. Let x represent the number of people and y the number of coins needed to purchase the items. Find the numberof people and the number of coins used to purchasethe items.

Mathematics
2 answers:
qaws [65]3 years ago
7 0

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kicyunya [14]3 years ago
4 0

Answer:

  • 7 people
  • 53 coins

Step-by-step explanation:

The problem statement tells us ...

  8x = y +3

  7x = y -4

Subtracting the second equation from the first gives ...

  x = 7

Then ...

  y = 7x +4 = 7·7 +4 = 53

There are 7 people, and 53 coins are required for purchase.

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guapka [62]

Area of the triangle: 1/2 x 6 x 8 = 24 square ft.

Area of half circle: 1/2 x 3.14 x 4^2 = 25.12 square feet.

Total area : 24 + 25.12 = 49.12 square feet.

3 0
2 years ago
Mark got 54 out of 66 in his maths test how many did he get wrong. Give your answer in its simplest form
alex41 [277]

Answer:

9/11 I think!

Step-by-step explanation:

54/66= 9/11

5 0
2 years ago
help in need help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Aleks [24]

answer is 2+ 1/4x + 1 the simplest form is x= -3/4 or -0.75
5 0
2 years ago
Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩
NISA [10]

Answer:

\theta = 108.29

Step-by-step explanation:

Given

u =

v =

Required:

Calculate the angle between u and v

The angle \theta is calculated as thus:

cos\theta = \frac{u.v}{|u|.|v|}

For a vector

A =

A = a * b

cos\theta = \frac{u.v}{|u|.|v|} becomes

cos\theta = \frac{.}{|u|.|v|}

cos\theta = \frac{2*6+4*-7}{|u|.|v|}

cos\theta = \frac{12-28}{|u|.|v|}

cos\theta = \frac{-16}{|u|.|v|}

For a vector

A =

|A| = \sqrt{a^2 + b^2}

So;

|u| = \sqrt{2^2 + 6^2}

|u| = \sqrt{4 + 36}

|u| = \sqrt{40}

|v| = \sqrt{4^2+(-7)^2}

|v| = \sqrt{16+49}

|v| = \sqrt{65}

So:

cos\theta = \frac{-16}{|u|.|v|}

cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}

cos\theta = \frac{-16}{\sqrt{2600}}

cos\theta = \frac{-16}{\sqrt{100*26}}

cos\theta = \frac{-16}{10\sqrt{26}}

cos\theta = \frac{-8}{5\sqrt{26}}

Take arccos of both sides

\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})

\theta = cos^{-1}(\frac{-8}{5 * 5.0990})

\theta = cos^{-1}(\frac{-8}{25.495})

\theta = cos^{-1}(-0.31378701706)

\theta = 108.288386087

<em></em>\theta = 108.29<em> (approximated)</em>

4 0
2 years ago
If you want points for freee.
romanna [79]

Answer:

WHA

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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