Answer: Option (b) is the correct answer.
Explanation:
The given data is as follows.
![[Ca^{2+}] = 2.1 \times 10^{-5}](https://tex.z-dn.net/?f=%5BCa%5E%7B2%2B%7D%5D%20%3D%202.1%20%5Ctimes%2010%5E%7B-5%7D)
M
![[C_{2}O_{4}^{2-}] = 4.75 \times 10^{-5}](https://tex.z-dn.net/?f=%5BC_%7B2%7DO_%7B4%7D%5E%7B2-%7D%5D%20%3D%204.75%20%5Ctimes%2010%5E%7B-5%7D)
M
As expression for 
will be as follows.
![K_{sp} = [Ca^{2+}][C_{2}O^{2-}_{4}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BCa%5E%7B2%2B%7D%5D%5BC_%7B2%7DO%5E%7B2-%7D_%7B4%7D%5D)
= 
And, expression for ionic product will be as follows.
Q = ![[Ca^{2+}][C_{2}O^{2-}_{4}]](https://tex.z-dn.net/?f=%5BCa%5E%7B2%2B%7D%5D%5BC_%7B2%7DO%5E%7B2-%7D_%7B4%7D%5D)
= 
= 
Since, it is shown here that ionic product is less that solubility product. Hence, no precipitate will form.
Thus, we can conclude that nothing will happen since Ksp > Q for all possible precipitants.
Answer:
True
Explanation:
I guessed XD But I also used Google and that's what I got
False, in all methods of charge transfer, friction, conduction, and induction, they all require at least contact between the objects.
Answer:
0.024M
Explanation:
Data obtained from the question include:
C1 = 6M
V1 = 2mL
C2 =?
V2 = 500mL
The molarity of the diluted solution can be obtained as follows:
C1V1 = C2V2
6 x 2 = C2 x 500
Divide both side by 500
C2 = (6 x 2) /500
C2 = 0.024M
The molarity of the diluted solution is 0.024M
Answer:
0.6 Ω
Explanation:
From the question given above, the following data were obtained:
Voltage (V) = 12 V
Current (I) = 20 A
Resistance (R) =?
From Ohm's law,
V = IR
Where:
V => is the voltage
I => is the current
R => R is the resistance
With the above formula, we can obtain the resistance as follow:
Voltage (V) = 12 V
Current (I) = 20 A
Resistance (R) =?
V = IR
12 = 20 × R
Divide both side by 20
R = 12 / 20
R = 0.6 Ω
Thus the resistance is 0.6 Ω
