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Genrish500 [490]
3 years ago
10

Why Lu* ion is highly hydrated?

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
This comment doesn’t matter
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PLEASE HELP MEEEEEEEEEEEEEEEEEEEEEEE
Genrish500 [490]

Answer:

Liquid

Explanation:

Gas is too far away, solid is close but it is not in a random pattern

4 0
3 years ago
Read 2 more answers
1.______ structure is achieved when a protein folds into a compact, three-dimensional between side-chain R groups of amino acids
kondor19780726 [428]

Answer:

The answer to your question is:

Explanation:

1._<u>Terciary</u>__ structure is achieved when a protein folds into a compact, three-dimensional between side-chain R groups of amino acids.

2._<u>Primary</u>___ structure is the sequence of amino acids in a protein.

3._<u>Secondary</u>___ structure describes the alpha helices and beta-sheets that are formed by hydrogen bonding between backbone atoms located near each other in the polypeptide chain.

4._<u>Quaternary</u>___ structure is the result of two or more protein subunits assembling to form a larger, biologically active protein complex.

5 0
3 years ago
Which is the strongest reducing agent in the periodic table?
ycow [4]
"Caesium" is the strongest reducing agent in Periodic table.

Hope this helps!
8 0
3 years ago
Read 2 more answers
Why are solutions considered mixtures?
Alex_Xolod [135]
Solute and solvent form a solution, which means two different kinds of molecules/atoms/compounds are mixed together, therefore, it is a mixture.
6 0
3 years ago
A large cylindrical tank contains 0.750 m3 of nitrogen gas at 27°C and 7.50 * 103 Pa (absolute pressure). The tank has a tight‐f
Nuetrik [128]

Answer: The answer is 68142.4 Pa

Explanation:

Given that the initial properties of the cylindrical tank are :

Volume V1= 0.750m3

Temperature T1= 27C

Pressure P1 =7.5*10^3 Pa= 7500Pa

Final properties of the tank after decrease in volume and increase in temperature :

Volume V2 =0.480m3

Temperature T2 = 157C

Pressure P2 =?

Applying the gas law equation (Charles and Boyle's laws combined)

P1V1/T1 = P2V2/T2

(7500 * 0.750)/27 =( P2 * 0.480)/157

P2 =(7500 * 0.750* 157) / (0.480 *27)

P2 = 883125/12.96

P2 = 68142.4Pa

Therefore the pressure of the cylindrical tank after decrease in volume and increase in temperature is 68142.4Pa

8 0
3 years ago
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