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frez [133]
3 years ago
5

One consequence of Einstein's theory of special relativity is that mass is a form of energy. This mass-energy relationship is pe

rhaps the most famous of all physics equations:
E=mc2,
where m is mass, c is the speed of the light, and E is the energy. In SI units, the units of speed are m/s. For the preceding equation to have consistent units (the same units on both sides of the equation), the units of E must be which of the following?
Physics
2 answers:
Zarrin [17]3 years ago
6 0

Answer:

Unit of energy is kg-m/s or Joules.

Explanation:

The mass- energy relationship in physics is given by :

E=mc^2

Where

m is the mass of the object

c is the speed of light

The SI unit of m is kilogram while the SI unit of c is as same as speed of light i.e. m/s. So, the unit of energy is kg-m/s. It is also equivalent to Joules.

So, the SI unit of energy is kg-m/s or Joules. Hence, this is the required solution.

atroni [7]3 years ago
6 0
Joule is the si unit for energy
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slab of ice floats on water with a large portion submerged beneath the water surface. The slab is in the shape of a rectangular
n200080 [17]

Answer:

a) \%V = 87.36\,\%, b) x = 1.248\,m, c) F_{B} = 176488.341\,N, d) Six polar bears.

Explanation:

a) The slab of ice is modelled by the Archimedes' Principles and the Newton's Laws, whose equation of equilibrium is:

\Sigma F =\rho_{w}\cdot g \cdot A \cdot x-\rho_{i}\cdot g\cdot V = 0

The height of the ice submerged is:

\rho_{w}\cdot A \cdot x = \rho_{i}\cdot V

x = \frac{\rho_{i}\cdot V}{\rho_{w}\cdot A}

x = \frac{\left(900\,\frac{kg}{m^{3}}\right)\cdot (20\,m^{3})}{\left(1030\,\frac{kg}{m^{3}} \right)\cdot (14\,m^{2})}

x = 1.248\,m

The percentage of the volume of the ice that is submerged is:

\%V = \frac{(1.248\,m)\cdot (14\,m^{2})}{20\,m^{3}} \times 100\,\%

\%V = 87.36\,\%

b) The height of the portion of the ice that is submerged is:

x = 1.248\,m

c) The buoyant force acting on the ice is:

F_{B} = \left(1030\,\frac{kg}{m^{3}} \right)\cdot (1.248\,m)\cdot (14\,m^{2})\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{B} = 176488.341\,N

d) The new system is modelled after the Archimedes' Principle and Newton's Laws:

\Sigma F = -n\cdot m_{bear}\cdot g-\rho_{i}\cdot V \cdot g + \rho_{w}\cdot V\cdot g = 0

The number of polar bear is cleared in the equation:

n\cdot m_{bear} = (\rho_{w} - \rho_{i})\cdot V

n = \frac{(\rho_{w}-\rho_{i})\cdot V}{m_{bear}}

n = \frac{\left(1030\,\frac{kg}{m^{3}} - 900\,\frac{kg}{m^{3}} \right)\cdot (20\,m^{3})}{400\,kg}

n = 6.5

The maximum number of polar bears that slab could support is 6.

8 0
3 years ago
Would it be easier to pull the tablecloth out from under a glass of water or an
Aleksandr-060686 [28]
Glass as it is heavier and by newtons first law and inertia the greater the mass = more inertia(resistance to chabge in motion) thus the glass has a greater mass than an empty paper cup and thus has greater inertia. So it would be easier to leave it in place
3 0
3 years ago
4
inna [77]

Answer:

5g/cm

Explanation:

denisty=mass/volume

100/20

5g/cm

8 0
3 years ago
A geosynchronous satellite orbits above the equator of Earth in a circular orbit, remaining in a fixed position with respect to
Anestetic [448]

Answer:

Explanation:

The relation between orbital period T and orbital radius R is as follows .

T² ∝ R³

T ∝ R¹°⁵

So time period of orbit is proportional to radius of orbit . Higher the height , larger the orbital period . As the orbital period is larger than required , the altitude of satellite must have been larger than required .

As mass of satellite  is not involved in the formula of orbital period , this is independent of mass of the satellite .

Hence the option C is correct .

8 0
3 years ago
Which of the following is NOT true for a spherical concave mirror? a. it cannot produce virtual images
dimulka [17.4K]

Answer:

Its focal length is positive

Explanation:

A concave mirror is shown in attached figure. The distance from the pole to the focus of the mirror is called its focal length. Spherical mirrors are a part of a sphere.

As per conventions, we know that the axis opposite to x axis is taken as negative.

So, it is clear that the focal length of spherical concave mirror is negative.

Hence, the incorrect option is (c) " its focal length is positive".

7 0
4 years ago
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