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Irina-Kira [14]
3 years ago
8

A block weighing 3.7 kg is suspended from the ceiling of a truck trailer by a hanging bungee cord. The cord has a cross-sectiona

l area 40 mm2 and an unstretched length of 43 cm.
The truck begins stopped at a red light on a state highway. While stopped, the block hangs straight down to a distance 53 cm below the hook that attaches the bungee cord to the ceiling of the truck.

(a) What is the Young's modulus of the cord?
Physics
1 answer:
sweet [91]3 years ago
5 0

Answer:

Y = 2.27 \times 10^{10} N/m^2

Explanation:

Natural length of the string is given as

L_o = 43 cm

length of the string while block is hanging on it

L = 53 cm

extension in length is given as

\Delta L = 10 cm

now we have strain in the string is given as

strain = \frac{\Delta L}{L}

strain = \frac{{10 cm}{43 cm}

strain = 0.23

similarly we will have cross-sectional area of the string is given as

A = 40 \times 10^{-6} m^2

now the stress in the string is given as

Stress = \frac{T}{A}

Stress = \frac{mg}{A}

Stress = \frac{3.7 \times 9.81}{40 \times 10^{-6}}

stress = 9.07 \times 10^5 N/m^2

Now Young's Modulus is given as

Y = \frac{stress}{strain}

Y = \frac{9.07 \times 10^5}{40\times 10^{-6}}

Y = 2.27 \times 10^{10} N/m^2

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