Question

When you drop a ball it accelerates downward at a rate of g. If you instead throw it downward, then its acceleration immediately after leaving your hand, assuming no air resistance, is
cannot say, unless the speed of "throw" is given
g
zero
less than g
more than g

Answer 1

The acceleration of the ball is always g

Explanation:

An object is said to be in free fall if there is only the force of gravity acting on it. In such situation, therefore, the net force on the ball is

$F=mg$ (1)

where

m is the mass of the ball

$g=9.8 m/s^2$ is the acceleration of gravity, pointing downward

Applying Newton's second law,

$F=ma$ (2)

where a is the acceleration, and equating (1) and (2), we find the acceleration of an object in free fall:

$mg=ma\\a=g$

So, any object in free fall has always an acceleration of $g$ (downward), regardless of its initial velocity.

Therefore, in this problem, it doesn't matter what is the direction of the initial velocity of the ball: its acceleration, in fact, will be always equal to g.

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