Answer:
Elastic potential energy, E = 200 J
Explanation:
It is given that,
Spring constant, K = 4 N/m 
initial stretching in the spring, x = 5 m
Finally, it is stretched an additional 5 m i.e. x' = 5 m        
Let E is the elastic energy in the spring after Varg stretches the spring. it is given by :


E = 200 J
So, the elastic energy in the spring after Varg stretches the spring is 200 J. hence, this is the required solution.
 
        
                    
             
        
        
        
Answer:

Explanation:
As we know that the speed of the sound is given as

now at t = 273 k = 0 degree

so we have


now when temperature is changed to 313 K we have

now we have



now from two equations we have

so we have


 
        
             
        
        
        
If you take a fluid (i.e. air or water) and heat it, the portion that is heated usually expands. The same mass takes up more volume and as a consequence the heated portion becomes less dense than the portion that is<span><span> not heated.</span> </span>
        
                    
             
        
        
        
Answer:
The gravitational acceleration of a planet of mass M and radius R
a = G*M/R^2.
In this case we have:
G = 6.67 x 10^-11 N (m/kg)^2
R = 2.32 x 10^7 m
M = 6.35 x 10^30 kg
Now we can compute:
a = (6.67*6.35/2.32^2)x10^(-11 + 30 - 2*7) m/s^2 = 786,907.32 m/s^2
The acceleration does not depend on the mass of the object.
 
        
             
        
        
        
When you drop an object on the moon, it falls to the ground.
But it only falls about 1/6 as fast as it falls on Earth.