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GaryK [48]
3 years ago
9

Is (2,2) a solution to this system of equations? x + 2y = 6 3x + 4y = 14

Mathematics
1 answer:
babymother [125]3 years ago
5 0

Answer:

No

Step-by-step explanation:

(2,2) isn't but  (6 1/2, -2) is because that is where they intercept

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What's the area of this rectangle?
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The area of this rectangle is 18 square units. What is the unit of measurement?

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18÷0.45
melomori [17]

Answer:

it is 40

Step-by-step explanation:

0.45 can go into 18 40 times

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The perimeter of a right triangle is 24 ft, and one of its legs measures 6 ft. Find the length of the other leg and the hypotenu
Mrrafil [7]

Answer:

Step-by-step explanation:

We know the perimeter of a triangle is the sum of all the sides( two legs and one hypotenuse).

By pythagoras we know that

h^2= a^2+b^2.

and the perimeter is P=h+a+b.

Since P=24 and a=6  we have these equations:

h^2=36+b^2\\24=h+6+b

From the last equation we have h=18-b. Replace h in the first equation we get that

(18-b)^2=36+b^2

18^2-36b+b^2=36+b^2\\288=36b\\b=\frac{288}{36}=8

and h=18-8=10

5 0
3 years ago
A map of a city shaped like a rectangle is given below on a grid. In 2012, there were 570 people per square kilometer) living in
Ksivusya [100]
570 were in the population in 2012
3 0
3 years ago
Given quadrilateral EFGH at e(-4,7) f(8,4) G(t,-5) and h(-7,-1) using coordinate geometry prove EFGH is a rectangle
Tcecarenko [31]

The above question was not properly written.

Complete Question

Given quadrilateral EFGH with vertices at E(-4,8), F(8,4), G(5,-5) and H(-7,-1), prove using coordinate geometry that EFGH is a rectangle.

Answer:

Quadrilateral EFGH is a rectangle.l because:

EF = GH and FG = EH

Step-by-step explanation:

The formula for coordinate geometry is given as :

√(x2 - x1)² + (y2 - y1)² when we have coordinates: (x1, y1) and (x2 , y2)

For the quadrilateral EFGH with given coordinates above to be a rectangle,

EF = GH

FG = EH

Hence:

For side EF

E(-4,8), F(8,4)

= √(8 - (-4))² + (4 - 8)²

= √12² + -4²

= √144 + 16

= √160 units

For side FG

F(8,4), G(5,-5)

=√(5 - 8)² + (-5 - 4)²

= √-3² + -9²

= √9 + 81

= √90 units

For Side GH

G(5,-5) , H(-7,-1)

= √(-7 - 5)² + (-1 - (-5))²

= √-12² + 4²

= √144 + 16

= √160 units

For side EH

E(-4,8), H(-7,-1)

= √(-7 -(-4))² +(-1 - 8)²

= √-3² + -9²

= √9 + 81

= √90 units

From the above calculation, we can see that truly,

EF = GH

FG = EH

Therefore, quadrilateral EFGH is a rectangle.

6 0
3 years ago
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