Question

At an ocean depth of 10 meters, a buoy bobs up and then down 6 meters from the ocean's depth. Ten seconds pass from the time the buoy is at its highest point to when it is at its lowest point. Assume at x = 0 the buoy is at normal ocean depth. Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

Answer 1

The sine function for the given scenario is y  = 6sin ( (π / 10) x )  -  10.

Step-by-step explanation:

The standard formula for sine function is Asin(Bx)+C.

A buoy bobs up and down 6 meters. That is the buoy shifts vertically and horizontally  for 6 meters which is amplitude.

∴Amplitude A= 6.

Period is the distance in the x-axis that makes one full oscillation.

We know that the time taken buoy to move from its highest point to lowest point (half oscillation) is 10 seconds.

∴The period for full oscillation is 20 seconds.

Also, Period =2π divided by B.

⇒ 20 (B) = 2π.

B=2π /20.

= π/ 10.

Since the buoy is in the depth of the ocean 10 meters C = -10.

Applying all the values in the formula,

⇒y  = 6sin ( (π/ 10) x )  -  10.

The first point is the mid line,

The first point is x=0,

⇒y=6sin(0)-10.

y= -10.

∴ The line starts at the point y = -10.

The second point is either maximum or minimum value.

That is (5,-4) and (15, -16.)