Answer:
97%.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
SiO2 (s) + 3C (s) —> SiC(s) + 2CO(g)
Next, we shall determine the mass of SO2 that reacted and the mass of SiC produced from the balanced equation. This is illustrated below:
Molar mass of SiO2 = 28 + (16x2) = 60 g/mol
Mass of SO2 from the balanced equation = 1 x 60 = 60 g
Molar mass of SiC = 28 + 12 = 40 g/mol
Mass of SiC from the balanced equation = 1 x 40 = 40 g.
From the balanced equation above,
60 g of SiO2 reacted to produce 40 g of SiC.
Next, we shall determine the theoretical yield of SiC. This can be obtained as follow:
From the balanced equation above,
60 g of SiO2 reacted to produce 40 g of SiC.
Therefore, 50.1 g of SiO2 will react to produce = (50.1 x 40)/60 = 33.4 g of SiC.
Therefore, the theoretical yield of SiC is 33.4 g
Finally, we shall determine the percentage yield of SiC as follow:
Actual yield of SiC = 32.3 g
Theoretical yield of SiC = 33.4 g
Percentage yield =?
Percentage yield = Actual yield /Theoretical yield x 100
Percentage yield = 32.3/33.4 x 100
Percentage yield = 96.7 ≈ 97%
Therefore, the percentage yield of the reaction is 97%.
