I believe the correct answer is atmosphere
Answer:
The empirical formula is same as the molecular formula = C6H10S2O
Explanation:
we start by dividing the percentage of each of the elements by their atomic mass
Carbon = 44.4/12 = 3.7
Hydrogen = 6.21/1 = 6.21
Sulphur = 39.5/32 = 1.234375
oxygen = 9.89/16 = 0.618125
That of oxygen is smallest so we divide all by that of oxygen
C = 3.7 / 0.618125 = 6
H = 6.21/ 0.618125 = 10
S = 1.234375/ 0.618125 = 2
Automatically, oxygen is 1
So the empirical formula is;
C6H10S2O
Let’s get its molecular formula. We multiply each of the subscript by the number;
(72 + 10 + 64 + 16)n= 162
162n = 162
n = 1
So the molecular formula is same as the empirical formula
Notice q=3/2, is half of the original q = 3(<span>1/2</span>)<span>t/28.8
your welcome
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Answer:
4.35 atm
Explanation:
According to the information given;
- Initial volume of the gas, V₁ is 2.50 L
- Initial pressure of the gas is standard pressure P₁, normally 1 atm
- New volume of the gas, V₂ is 575 mL
We are required to determine the new pressure of the gas, P₂ ;
To answer the question, we are going to use the Boyle's law, that relates pressure and volume at constant temperature.
According to Boyle's law;
P₁V₁ = P₂V₂
Therefore, to determine the new pressure, P₂, we rearrange the formula;
New pressure, P₂ = P₁V₁ ÷ V₂
Thus;
P₂ = ( 1 atm × 2.50 L) ÷ 0.575 L
= 4.3478 atm
= 4.35 atm
Therefore, the new pressure of the gas is 4.35 atm
