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Anni [7]
4 years ago
11

34 Points!! 17 Each Points Please Help ASAP!! View Attached Image!! Will Mark Brainliest If All Are Answered!!

Chemistry
1 answer:
Katarina [22]4 years ago
4 0

Answer:

I think it is A _ B_C_D

Explanation:

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If an ice cube melts at 0oC but water also freezes at 0oC, what is the difference between melting and freezing in terms of (a) t
zalisa [80]
The energy involved in melting in freezing is heat, At 0 degrees Celsius ice is at an equilibrium where the heat energy absorbed during melting (endothermic) and heat energy dispersed during freezing (exothermic). When ice melts its absorbs heat energy to change states, when water freezes to ice it dispersed heat energy so that the particles can move slow enough to be almost frozen, but still very small vibrations throughout the ice. Particles in the frozen state are packed tightly and help together by a crystal lattice and IMF's, liquid is free flowing with free floating particles that can move freely from one another particle. 
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3 years ago
The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure
Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature T_1

P_2 = vapor pressure at temperature T_2

\Delta H_{vap} = Enthalpy of vaporization  

R = Gas constant = 8.314 J/mol K

1) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =363 K

T_2 = final temperature =373 K

P_2=1 atm, P_1=?

Putting values in above equation, we get:

\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]

P_1=0.69671 atm \approx 0.6970 atm

The vapor pressure at temperature 363 K is 0.6970 atm

2) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =373 K

T_2 = final temperature =383 K

P_1=1 atm, P_2?

Putting values in above equation, we get:

\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]

P_2=1.4084 atm \approx 1.410 atm

The vapor pressure at 383 K is 1.410 atm

8 0
3 years ago
The formula for ammonium carbonate:
Dima020 [189]

Ammonium is NH₄⁺ and Carbonate is CO₃⁻² => Ammonium Carbonate is (NH₄)₂CO₃

6 0
4 years ago
What effect do calcium ions have on the water in ecosystems?
Marysya12 [62]
It's because they add to its hardness . Calcium is naturally dissolved in water
6 0
3 years ago
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At stp 5.6 liters of ch4 which element contains the same number of molecules?
Alinara [238K]

Answer:

5.6 L of hydrogen

Explanation:

when 5.6 liter is added of hydrogen, the value equallify and becomes right

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