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2 years ago

You would be most likely to use a slicing machine if you were using the __________ method to produce cookies.

1 answer:

7 0

You would be most likely to use a slicing machine if you were using the <u>icebox </u>method to produce cookies.

In the icebox method a type of cookie in which the dough is made, rolled into a stick, and refrigerated until the dough hardens. The dough can be removed from the refrigerator, cut into individual pieces, and then baked. The rest of the dough is returned to the refrigerator until needed.

Icebox method, also known as refrigerator cookies, are sliced and baked cookies. The dough is formed into logs, chilled in the refrigerator (also called an icebox), sliced , and then baked.

Learn more about the Icebox method here,

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A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a solution that is 2.1 × 10-5 M in calcium ion and 4.75

Mkey [24]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

$[Ca^{2+}] = 2.1 \times 10^{-5}$ M

$[C_{2}O_{4}^{2-}] = 4.75 \times 10^{-5}$ M

$K_{sp} (CaC_{2}O_{4}) = 2.3 \times 10^{-9}$

As expression for $K_{sp}$ will be as follows.

$K_{sp} = [Ca^{2+}][C_{2}O^{2-}_{4}]$

= $2.3 \times 10^{-9}$

And, expression for ionic product will be as follows.

Q = $[Ca^{2+}][C_{2}O^{2-}_{4}]$

= $2.1 \times 10^{-5} \times 4.75 \times 10^{-5}$

= $9.975 \times 10^{-10}$

Since, it is shown here that ionic product is less that solubility product. Hence, no precipitate will form.

Thus, we can conclude that nothing will happen since Ksp > Q for all possible precipitants.

3 0

3 years ago

Wich tools are appropriate to determine the densety of an irregular-shaped object ?

Svetach [21]

Answer:

The most accurate way to determine an object's volume, especially in the case of an irregularly shaped object, is to immerse it in water and measure the amount of water it displaces. A graduated cylinder large enough to hold both the object and enough water to fully immerse it is the best tool for this job.

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4 years ago

CH4 + 202 → CO2 + 2H2O<br> How many grams of O2 needed to react with 2 moles of CH4?

PtichkaEL [24]

<h3>Answer:</h3>

100 g O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 2 mol CH₄

[Solve] x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CH₄ → 2 mol O₂

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

<u>Step 3: Stoichiometry</u>

Set up conversion: $\displaystyle 2 \ mol \ CH_4(\frac{2 \ mol \ O_2}{1 \ mol \ CH_4})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})$
Multiply/Divide: $\displaystyle 128 \ g \ O_2$