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natali 33 [55]
1 year ago
8

You would be most likely to use a slicing machine if you were using the __________ method to produce cookies.

Chemistry
1 answer:
Verizon [17]1 year ago
7 0

You would be most likely to use a slicing machine if you were using the <u>icebox </u>method to produce cookies.

In the icebox method a type of cookie in which the dough is made, rolled into a stick, and refrigerated until the dough hardens. The dough can be removed from the refrigerator, cut into individual pieces, and then baked. The rest of the dough is returned to the refrigerator until needed.

Icebox method, also known as refrigerator cookies, are sliced ​​and baked cookies. The dough is formed into logs, chilled in the refrigerator (also called an icebox), sliced ​​, and then baked.

Learn more about the Icebox method here,

https://brainly.in/question/1513677

#SPJ4

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How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?
balu736 [363]

The given question is incomplete. The complete question is:

How much heat is produced when 24.8 g of CH_4 is burned in excess oxygen gas

Given: CH _4&#10;+2O_2\rightarrow CO_2+2H_2O  ΔH= −802 kJ.

Answer: 1243.1 kJ

Explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of  1 mole of methane = 802 kJ kJ/mol

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of CH_4 weighs = 16 g  

Thus we can say:  

16 g of CH_4 on combustion releases heat = 802 kJ

Thus 24.8 g of CH_4 on combustion releases =\frac{802}{16}\times 24.8=1243.1kJ

Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ

4 0
3 years ago
Use the equation: 2 kclo3 2 kcl + 3 o2 to write the mole ratio needed to calculate: (a) moles of kcl produced from 3.5 moles of
poizon [28]

Answer:-

(a) 3.5

(b) 3

Explanation:-

2KClO3 --> 2KCl + 3 O2

From the equation we see that 2 moles of KClO3 gives 2 moles of KCl.

So 3.5 moles of KClO3 will give 3 moles of KCl.

Again

3 moles of O2 are produced with 2 moles of KCl.

If 4.5 moles of O2 produced then

moles of KCl = 4.5 x 2/3

=3

3 0
3 years ago
Nitric acid (HNO3) is a strong acid that is completely ionized in aqueous solutions of concentrations ranging from 1% to 10% (1.
Alborosie

<u>Given:</u>

Concentration of HNO3 = 7.50 M

% dissociation of HNO3 = 33%

<u>To determine:</u>

The Ka of HNO3

<u>Explanation:</u>

Based on the given data

[H+] = [NO3-] = 33%[HNO3] = 0.33*7.50 = 2.48 M

The dissociation equilibrium is-

            HNO3   ↔    H+      +      NO3-

I            7.50               0                 0

C          -2.48          +2.48              +2.48

E            5.02            2.48              2.48

Ka = [H+][NO3-]/HNO3 = (2.48)²/5.02 = 1.23

Ans: Ka for HNO3 = 1.23

6 0
3 years ago
Are the particles in a solid in constant motion, or are they "frozen in place?"
Tems11 [23]
The molecules are frozen in place but still vibrate
3 0
3 years ago
Read 2 more answers
The atomic particles given off as a result of nuclear fusion are?
Vilka [71]

Answer:

I think <em><u>alpha</u></em> and <em><u>beta</u></em> is the answer.

4 0
3 years ago
Read 2 more answers
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