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Likurg_2 [28]
2 years ago
9

The circumference is 12 mile. What is the diameter?

Mathematics
2 answers:
photoshop1234 [79]2 years ago
8 0

To find the diameter of a circle, using only the circumference, you need to divide the circumference by π, or 3.14.

So in this case, you must divide 12 by 3.14, which gives you 3.82.

I even double checked this, and should be correct then.

SashulF [63]2 years ago
3 0

Answer:

The diameter is approximately 3.8 mi

Step-by-step explanation:

The circumference formula is C = πd.  Dividing both sides by π results in a formula for d (diameter) when C is known:

d = C / π

In this case, with C = 12 mi,

d = 12 mi / π, or approximately 3.8 mi

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7 0
3 years ago
A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and
goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}

Solve for S(t):

\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}

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The left side is the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}

Integrate both sides:

e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt

e^{t/800}S(t)=64e^{t/800}+C

S(t)=64+Ce^{-t/800}

There's no sugar in the water at the start, so (a) S(0) = 0, which gives

0=64+C\impleis C=-64

and so (b) the amount of sugar in the tank at time t is

S(t)=64\left(1-e^{-t/800}\right)

As t\to\infty, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.

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3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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