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Hoochie [10]
4 years ago
6

Please answer this question correctly for 24 points and brainliest!!

Mathematics
1 answer:
amm18124 years ago
8 0

Answer:

  $110

Step-by-step explanation:

Let a, b, and c represent the earnings of Alan, Bob, and Charles. The problem statement tells us ...

  a + b + c = 480 . . . . . . the combined total of their earnings

  -a + b = 40 . . . . . . . . . . Bob earned 40 more than Alan

  2a - c = 0 . . . . . . . . . . . Charles earned twice as much as Alan

Adding the first and third equations, we get ...

  (a + b + c) + (2a - c) = (480) + (0)

  3a + b = 480

Subtracting the second equation gives ...

  (3a +b) - (-a +b) = (480) -(40)

  4a = 440 . . . . . . . . simplify

  a = 110 . . . . . . . . . . divide by the coefficient of a

Alan earned $110.

_____

<em>Check</em>

Bob earned $40 more, so $150. Charles earned twice as much, so $220.

The total is then $110 +150 +220 = $480 . . . . as required

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Step-by-step explanation:

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25-5=20$

20-5=15$

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What is the solution of this equation? 3a = 18
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3a =18

3a/3 = 18/3

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Hope this helps
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In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll
maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_x\ p^x(q)^{n-x}, where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5

Hence, the probability rounded to the nearest tenth that fewer than 4 of them will say that football is their favorite sport =0.5

4 0
3 years ago
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