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sergejj [24]
3 years ago
5

DESPERATE, PLEASE HELP!! Triangle ABC and Triangle PQR are similar. Triangle ABC is dilated by a scale factor of 1.25 and rotate

d 45 degrees counterclockwise about point B to form triangle PQR. The side lengths of triangle ABC are line AB, 5 units; line BC 4.2 units; and line AC 4 units. Match each side of triangle PQR to its length. CHOICES 5.25 units, 5 units, 6.25 units match which side PQ, QR, and PR
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

PQ = 1.25 * AB = 1.25 * 5 = 6.25


QR = 5,25 and PQ = 5 units

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I need help with this math problem ASAP plsssss helppp. The problem is attached below
PolarNik [594]

Answer:

234.67 in³

Step-by-step explanation:

volume of full sphere = 4/3(π)(r³) = 4/3(3.14)(5³) = 523.33 in³

volume of half sphere = 523.33/2 = 261.67 in³

volume of cube = LWH = 3³ = 27 in³

261.67 - 27 = 234.67 in³

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3 years ago
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A central angle theta in a circle of radius 7 m is subtended by an arc of length 8 m. Find the measure of theta in degrees. (Rou
gogolik [260]

Answer: In degrees , The measure of \theta=65.5^{\circ}

In radians , the measure of  \theta =\dfrac{8}{7}\text{ radians}.

Step-by-step explanation:

We know that the formula for length of arc is given by :-

l=\theta r

, where \theta = Central angle subtended by arc.

r= radius of the circle.

As per given , we have

Radius of circle : r=7 m

Length of arc : l=  8 m

Substitute these values in the above formula , we get

8=\theta (7)\\\\\Rightarrow\ \theta =\dfrac{8}{7}\text{ radians}

Hence, the measure of \theta =\dfrac{8}{7}\text{ radians}.

To convert it into degrees we multiply it with \dfrac{180^{\circ}}{\pi}

The measure of \theta =\dfrac{8}{7}\times\dfrac{180^{\circ}}{\pi}

=(\dfrac{8\times180}{7\times3.14})^{\circ}=65.5141037307^{\circ}

\approx65.5^{\circ}

Hence, the measure of \theta=65.5^{\circ}

8 0
3 years ago
Question 15 of 20
grandymaker [24]

Answer: 3 inches

Step-by-step explanation:

4 0
2 years ago
What are the ordered pairs of the
9966 [12]

Start by writing the system down, I will use y to represent f(x)

y=x^2-5x+3\wedge y=-3

Substitute the fact that y=-3 into the first equation to get,

-3=x^2-5x+3

Simplify into a quadratic form (ax^2+bx+c=0),

x^2-5x+6=0

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

x^2+x(m+n)+mn=0

which then must factor into

(x+m)(x+n)=0

And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

So as mentioned, solutions will equal to m=3, n=2 but these are just x-values in the solution pairs of a form (x,y).

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are (2,0) and (3,0).

Hope this helps :)

5 0
2 years ago
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