All categories

3 years ago

HELP Increase 1 by 10%

Mathematics

2 answers:

jek_recluse [69]3 years ago

8 0

Answer:

1.1

Step-by-step explanation:

Rus_ich [418]3 years ago

5 0

Answer:

The answer is 1.1

Step-by-step explanation:

To increase 1 by 10%, you have to do this:

1 * 10% = 0.1

The 0.1 is what 10% of 1 is.

You then add that 0.1 to the 1:

0.1 + 1 = 1.1

And that is how you get the answer.

<h2>Mark Me Brainliest Please</h2>

You might be interested in

HELP!!!

MakcuM [25]

Answer:

based on my experience mind you're answer.

8 0

1 year ago

If y-1<br> ______= 10 then y =<br> y

dimulka [17.4K]

Answer:

B -1/9

Step-by-step explanation:

(y - 1) / y = 10

y - 1 = 10y

- 1 = 9y

y = -1/9

4 0

3 years ago

Alex scored 98,72, and 87 on his first three math test. What must he score on the next test to have an average of at least 86 (P

ss7ja [257]

Answer:

$\huge\boxed{\text{At least an } 87\%}$

Step-by-step explanation:

In order to find what score Alex must earn to have an average of 86 on all his tests, we need to first note what the formula to find the average of a data set is.

$\displaystyle \frac{x_1+x_2+...x_n}{n}$

What the formula means is that we have to add up all the values then divide by the total number of values.

Let's represent our unknown number as $x$ .

$\displaystyle \frac{98+72+87+x}{4} \geq 86$ (since we want AT LEAST an 86).

Let's solve this inequality for x.

$\frac{98+72+87+x}{4} \cdot 4 \geq 86 \cdot 4$
$98+72+87+x \geq 344$
$257 + x \geq 344$
$257 + x - 257 \geq 344 - 257$
$x \geq 87$

So, Alex must score at least an 87% on his next quiz to have an average of 86%.

Hope this helped!

8 0

3 years ago

3 friends have a dinner in a restaurant. The total bill for the dinner is $41. The friends leave 15% tip and they want to divide

nekit [7.7K]

$41 x 15% = $6.15/4 = 1.5375 if you round up you would get $1.54 as your asnwer.

4 0

4 years ago

Please Help<br> Will give brainliest

Serhud [2]

Answer:

D. x^4

Step-by-step explanation:

♪＼(*＾▽＾*)／＼(*＾▽＾*)／

3 0

3 years ago