Which angle number represents <DHL

81(p+q)^2-9p-9q Factor this

polet [3.4K]

Answer:

9(p + q)(9p + 9q - 1)

Step-by-step explanation:

Given

81(p + q)² - 9p - 9q ← factor out - 9 from these 2 terms

= 81(p + q)² - 9(p + q) ← factor out 9(p + q) from each term

= 9(p + q)(9(p + q) - 1)

= 9(p + q)(9p + 9q - 1)

8 0

2 years ago

Read 2 more answers

( 6 , -10 ) y (-15 , 15 ) Finding slope from two points :)

svet-max [94.6K]

Answer:

-25/21

Step-by-step explanation:

m=(y2-y1)/(x2-x1)=(15-(-10))/(-15-6)=(15+10)/-21=25/-21

5 0

2 years ago

The number 12,300 is written ______. as a coefficient in standard form in scientific notation

dexar [7]

The number 12,300 is written 1.23 x 10⁴ as a scientific notation. It's coefficient is 1.23; base is 10⁴ in exponent form.

Scientific notation is a method developed by scientists to shorten the number that expresses a very large number. The scientific notation is based on powers of the base number 10.

Scientific notation has two numbers: coefficient and base. The coefficient must be greater than or equal to 1 and less than 10. The base is always 10 written in exponent form.

12,300 as coefficient in standard form in scientific notation.

1) put decimal after the first digit and drop the zeros. from 12,300 to 1.23 this is the coefficient.

2) to find the exponent, count the number of places from decimal to the end of the number.
1.2300 ; there are 4 places

So the scientific notation is 1.23 x 10⁴

6 0

2 years ago

33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

2 years ago

Angles T and V are country that angle T has a measure of (2X +10) angle B has a measure of 48° what is the value of X

enyata [817]

If T and V are complementary angles, their sum is 90°.

V + T = 90°
48° + (2X+10)° = 90° . . . . . . . substitute given information
2X + 58 = 90 . . . . . . . . . . . . .. collect terms
2X = 32 . . . . . . . . . . . . . . . . .. subtract 58
X = 16 . . . . . . . . . . . . . . . . . .. divide by 2

The value of X is 16.

4 0

2 years ago