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zhuklara [117]
3 years ago
6

A jet flies over the Air Force Base at 10:20 a.m. At 10:32 a.m., the plane passes over the Navy Base Station, 120 miles away. Ho

w fast is the aircraft traveling?
Mathematics
1 answer:
kati45 [8]3 years ago
3 0
So first calculate the time between the plane flied over the Air Force Bases (AFB) and Navy Base Station (NBS):
(time passed Air Force Bases) - (time passed Air Force Bases) = 10:32 - 10:20 = 12 mins
Since we know the distance that plane travel from AFB to NBS is 120 miles and the plane traveled that distance within 12 minutes.
We have
120 miles / 12 minutes = 10 miles / minute
Calculate it into miles per hour (60 minutes):
10 miles/minute x 60 minutes = 600 miles per hour.
ANSWER : 600 mph
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3 years ago
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Answer:

2

Step-by-step explanation:

5 0
3 years ago
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sukhopar [10]

The external angle is suplementary to the internal angle close to it. We also know that the sum of all the internal angles of the triangle are equal to 180 degrees, this means that the angle "a" is suplementary to the sum of the angles "b" and "c". Through this logic, we can conclude that since:

\begin{gathered} \angle d=180-\angle a \\ \angle b+\angle c=180-\angle a \end{gathered}

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\angle d=\angle b+\angle c

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Let's use an example:

On this example, the external angle is 120 degrees, therefore the sum of the remote interior angles must also be equal to that. Let's try:

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The sum of the remote interior angles is equal to the external angle.

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1 year ago
F(x) = (x - c)(x + c), find the y-intercepts of the inverse of f(x).
Allushta [10]

Answer:

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Step-by-step explanation:

8 0
2 years ago
I need this one answered too, I'm not very good at fractions...
gizmo_the_mogwai [7]

b is correct! good job :)

4 0
3 years ago
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