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3 years ago

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A given substance is , meaning that is can easily pass through fatty substances and mix with them freely. However, this substanc

e does not mix well with molecules that are polar. Only substances mix well with polar molecules.

1 answer:

zhuklara [117]3 years ago

8 0

The substance is probably an Organic Solvent.

Organic solvents are capable of reacting with fatty acids and mixing with fatty substances but does not mix well with polar substances such as water.

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A set of headphones produces sounds that cancel out sound waves from the

Basile [38]

Answer:

C. Destructive interference

Explanation:

<em>Destructive interference</em> is when there are two waves <u>with the same frequency</u>, and the peaks of one wave (the highest points) line up with the valleys (the lowest points) of the second one.

Constructive interference would cause the sound to be louder.

Absorption and reflection are interactions that would not take into account the fact that the headphones produce sounds.

4 0

4 years ago

What do measurements of the mass of the Milky Way indicate?

miv72 [106K]

<span>That the mass is far lesser and distributed mistakenly, as compared to what the orbits of stars declare it should be. Stars orbit more rapidly than the mass would predict, particularly out toward the galactic edge. This means that there is more mass than has been measured, and that it is spread out in a huge cloud around the galaxy. This is one of the reasons why scientists believe that dark matter exists.</span>

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4 years ago

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

uysha [10]

Answer:

The wavelength of the line in the absorption line spectrum of hydrogen caused by transition is 657.1 nm.

Explanation:

Energy of the electron in a hydrogen atom in nth shell:

$E=\frac{-R_y}{n^2}$

$R_y=2.178\times 10^{-18} J$

Energy of an electron in n = 2:

$E_2=\frac{-R_y}{2^2}=-\frac{R_y}{4}$

Energy of an electron in n = 3:

$E_3=\frac{-R_y}{3^2}=-\frac{R_y}{9}$

Energy difference in between both the shells:

$\Delta E=E_3-E_2$ :

$=-\frac{R_y}{9}-(-\frac{R_y}{4})=\frac{5R_y}{36}$

$\Delta E=\frac{5R_y}{36} =\frac{5\times 2.178\times 10^{-18} J}{36}$

$=3.025\times 10^{-19} J$

$\Delta E=3.025\times 10^{-19} J=\frac{hc}{\lambda}$

$\lambda =\frac{hc\times 36}{3.025\times 10^{-19} J}$

= $\frac{6.626\times 10^{-34} J s\times 3\times 10^8 m/s}{3.025\times 10^{-19} J}$

$\lambda =6.571\times 10^{-7} m=657.1 nm$

$1 m = 10^9 nm$

The wavelength of the line in the absorption line spectrum of hydrogen caused by transition is 657.1 nm.

8 0

4 years ago

Why do nonmetals tend to form anions when they react to form compounds?

Maslowich

Yes they do nonmetals form anions and metals form cations

8 0

4 years ago

Calculate the solubility of ( = ) in moles per liter. Ignore any acid–base properties. s = mol/L Calculate the solubility of ( =

BaLLatris [955]

This is an incomplete question, here is a complete question.

Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.

CaCO₃, Ksp = 8.7 × 10⁻⁹

Answer : The solubility of CaCO₃ is, $9.33\times 10^{-5}mol/L$

Explanation :

As we know that CaCO₃ dissociates to give $Ca^{2+}$ ion and $CO_3^{2-}$ ion.

The solubility equilibrium reaction will be:

$CaCO_3\rightleftharpoons Ca^{2+}+CO_3^{2-}$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ca^{2+}][CO_3^{2-}]$

Let solubility of CaCO₃ be, 's'

$K_{sp}=(s)\times (s)$

$K_{sp}=s^2$

$8.7\times 10^{-9}=s^2$

$s=9.33\times 10^{-5}mol/L$

Therefore, the solubility of CaCO₃ is, $9.33\times 10^{-5}mol/L$

4 0

3 years ago