Answer:the number of moles represented by 3.0 x 10^24 atoms of Ag is 0.500mol 0.500 m o l .
Explanation:
Answer:
The equipments you should have ready to start the crucible experiment includes: safety goggles, crucible with lid, crucible tong, ring support with clay triangle, Bunsen burner and heat resistant tile.
Explanation:
Crucible is an equipment in the laboratory which is suitable for heating a sample to extreme heat over a flame, Modern laboratory crucible are made up of graphite- based composite materials for achievement of higher performance. Because extreme heat is involved, you should locate the correct labware for the experiment, including the equipment to safely handle and support the crucible. These equipments includes:
--> Safety goggles: Because you will work with chemical it is advisable to use a safety goggles which protects the eyes from dangerous floating chemical aerosol.
--> crucible with lid: This is the main apparatus with the lid (cover) which is used to cover the crucible to prevent spilling of the boiling chemical.
--> Crucible tong: These are scissors like tools used to grasp hot crucible.
--> Ring support with clay triangle: the clay triangle is used to hold crucible when they are being heated. They usually sit on a ring stand.
--> Bunsen burner: Produces a single open gas flame which can be used for heating.
With the safety equipments listed above, you can carry out experiment using the crucible. These equipments helps minimise laboratory hazard that may occur should Incase it's not available.
Answer:
C₃H₃NaO₂
Explanation:
The percentage composition of the artificial snow is given.
The smallest whole number ratio of the atoms in a compound gives the empirical formula.
To find the empirical formula of the artificial snow, we use the method below;
Percentage composition of oxygen = 100 - (38.3+3.33+ 24.4) = 33.97
Elements C H Na O
Percentage
Composition 38.3 3.22 24.4 33.97
Number of
moles 38.3/12 3.22/1 24.4/23 33.97/16
3.19 3.22 1.06 2.12
Divide by
the smallest 3.19/1.06 3.22/1.06 1.06/1.06 2.12/1.06
3 3 1 2
The empirical formula of the compound is C₃H₃NaO₂
