O they did not
at least thats what my substitute teacher said
Looks like 3*.5 mol of N, or 1.5*.5 N2
<span>convert that to grams.</span>
Answer:
0.72 g of the lower oxide gave 0.8 g of higher oxide when oxidised. ... Thus, 90g of lower oxide contains as much metal as 100g of higher oxide, i.e., 80g (given). Hence, 80g of metal combines with 10g of oxygen in the lower oxide and 20g of oxygen in the higher oxide.
Answer : The equilibrium constant for this reaction is, 
Explanation :
The given main chemical reaction is:
; 
The intermediate reactions are:
(1)
; 
(2)
; 
We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:
(1)
; 
(2)
; 
Thus, the equilibrium constant for this reaction will be:


Thus, the equilibrium constant for this reaction is, 