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vovikov84 [41]
3 years ago
13

The figure shows a kite inside a rectangle. Which expression represents the area of the shaded region? 2x2 4x2 6x2 8x2

Mathematics
2 answers:
notka56 [123]3 years ago
5 0
The picture in the attached figure

we know that
area of the <span>the shaded region=area of rectangle -area of a kite

area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²

area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²

area of the the shaded region=8x²-4x²-----> 4x²

the answer is 
4x²

zhuklara [117]3 years ago
3 0

Answer:

B.)4x²

Step-by-step explanation:

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Sajia has 30 Books in her library. she sold 9 books at the thrift store on Saturday. Write and solve and inequality to determine
ELEN [110]

Sajia can sell 21 books she can sell if she comes back on sunday and the required inequality is 9 + x \leq 30

<em><u>Solution:</u></em>

Given that Sajia has 30 Books in her library

She sold 9 books at the thrift store on Saturday

To find: We have to write and solve an inequality to determine number of more books she can sell if she comes back on sunday

Let "x" be the number of more books she can sell if she comes back on sunday

<em><u>We can write a inequality as:</u></em>

\text{ books already sold } + \text{ number of books remaining } \leq \text{ total number of books she has }

9 + x \leq 30

Now moving 9 from L.H.S to R.H.S we get,

x \leq 30 - 9

On solving 30 - 9 = 21,

x \leq 21

So Sajia can sell 21 books she can sell if she comes back on sunday

6 0
3 years ago
Which of the following are considered measures of center?
goldenfox [79]

Answer:

only 1 and 2

(mean and median)

the mean absolute deviation is the measure of variability

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
∠A and \angle B∠B are supplementary angles. If m\angle A=(7x+10)^{\circ}∠A=(7x+10) ∘ and m\angle B=(7x-26)^{\circ}∠B=(7x−26) ∘ ,
blsea [12.9K]

Answer:

108 degrees

Step-by-step explanation:

Since angles A and B are supplementary, they both add up to 180. Angle A = 7x+10, and angle B = 7x-26. You can set up the equation A + B = 180, and then plug in angles A and B, which gives you 7x+10 + 7x-26 = 180. Then you just need to isolate x:

Combine like terms: 14x - 16 = 180

Add 16 to both sides: 14x = 196

Divide both sides by 14: x = 14

Now that you know x, you can plug it into the expression for angle A (7x+10):

A = 7(14) + 10 = 98+10 = 108

5 0
3 years ago
The perimeter of a square is 96m.Find its area.
nadya68 [22]
<h3>Solution</h3>

P = 4a

96 = 4a

a = 24 m

so, the area is

A = a²

A = 24²

A = 24 × 24

A = 576 m²

4 0
2 years ago
Read 2 more answers
Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
mafiozo [28]

Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0
3 years ago
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