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3 years ago

find the slope and y-intercept of the line in the graph. Express the answers as simplified fractions, if necessary.

Mathematics

1 answer:

ruslelena [56]3 years ago

3 0

Answer:

y=1 3/5x+-5

Step-by-step explanation:

So the y intercept is where your slope meets the middle, basically the y. So it hit the y on -5. And the rise and run 8/5 rise is 8 and run is 5. 8/5= 1 3/5. in equation it is y=1 3/5x+-5.

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-2(2x+3)=-(x+1)-2 whats x

AysviL [449]

Answer:

x=-1

Step-by-step explanation:

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4 years ago

Many poker games start with each player being dealt five cards, called the player's "hand". Remember, there are 52 cards in a st

jek_recluse [69]

Answer:

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3 years ago

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natita [175]

Answer:

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Step-by-step explanation:

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3 years ago

10 points

Inessa05 [86]

Answer:

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4 0

3 years ago

Read 2 more answers

I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

================================================

Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

6 0

3 years ago