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OlgaM077 [116]
3 years ago
11

HELP WITH TRIANGLES & ANGLES PLEASE AND THANK YOU!

Mathematics
1 answer:
Lerok [7]3 years ago
4 0
Right or acute, not sure. hope this helped If its rly important go with acute
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Answer: Maybe it's the third one I'm not completely sure. don't take my word for it.

Step-by-step explanation:

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Dave's bank account balance reads -$345. What does this mean?
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Answer:

hes in debt 345 dollars

Step-by-step explanation:

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3 years ago
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What is the value of x?<br><br><br><br> Enter your answer in the box.
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The sum of all angle measures in a heptagon in 900°. We will subtract all of these angles from 900 to find our answer.

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2 years ago
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If f(x) = 4x-x², find<br> square root f(3/2)
katrin [286]

Answer:

\frac{\sqrt{15} }{2}

Step-by-step explanation:

\sqrt{f(\frac{3}{2} ) , substitute \frac{3}{2} to x

f(\frac{3}{2} )=4(\frac{3}{2} )-(\frac{3}{2} )^2 = \frac{15}{4} or 3.75

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6 0
1 year ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
2 years ago
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