The correct answer is 47/6 or 7 5/6
To find this we need to first make them improper fractions instead of mixed numbers. You can do this by multiplying the whole number by the bottom (denominator) and adding it to the top (numberator). Then putting it over the bottom again. He's this in action:
-2 1/3
3*2 + 1 = 7
-7/3
So the first term is actually -7/3. Lets do the same for the second.
-10 1/6
6*10 + 1 = 61
-61/10
Now that we have these, we can give them common denominators and complete the action.
-7/3 - (-61/6)
-14/6 + 61/6
47/6 or 7 5/6
The answer is 80 you divide 240.00 into 3 and get 80
32 because it is the same shape and it has same angle
Answer:
Step-by-step explanation:
umm like 2.8 i think
The length of the photograph is <u> 10 </u> inches.
Explanation:
Given, Width of a photograph is x.
Length of the photograph is 3 inches longer than its width. i.e. x + 3.
Area of the photograph = x(x+3)
If its area is 70 square inches, then
x(x+3)=70
![x^2 + 3x = 70](https://tex.z-dn.net/?f=x%5E2%20%2B%203x%20%3D%2070)
![x^2 + 3x-70 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%203x-70%20%3D%200)
![x^2 - 7x + 10x-70 = 0](https://tex.z-dn.net/?f=x%5E2%20-%207x%20%2B%2010x-70%20%3D%200)
x(x-7)+10(x-7)=0
(x+10)(x-7) =0
x+10=0; x-7 = 0
x = -10 and x = 7
Width of the photograph must not be in negative value. So, we can ignore –10.
Therefore, width of the photograph, x = 7 inches.
Now, the length of the photograph = 7 + 3 = 10 inches.
Thus, the required length of the photograph is 10 inches.