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Oliga [24]
4 years ago
15

If a magnet is broken into two pieces, what happens to the magnetic poles? One piece will have a north pole, while the other pie

ce will have a south pole. Each piece will still have a north pole and a south pole. Each piece will have only a north pole. Both pieces will no longer have any magnetic poles.
Physics
2 answers:
Yuri [45]4 years ago
5 0
Each piece will still have a North and South Pole
zalisa [80]4 years ago
5 0
<span>If a magnet is broken into two pieces, each piece
will still have a north pole and a south pole.</span>
You might be interested in
If a bicycle is going 8 m/s for 29 seconds how far does it go?
VladimirAG [237]

Answer:

232

Explanation:

D=S*T

(By distance formula)

8*29=

232

4 0
3 years ago
A marathon runner completes a 42.238 km course in 2 h, 31 min, and 46 s . There is an uncertainty of 29 m in the distance run an
icang [17]

Answer:

The percentage uncertainty in the average speed is 0.10% (2 sig. fig.)

Explanation:

Consider the formula for average speed \bar{v}.

\displaystyle \bar{v} = \frac{s}{t},

where

  • s is the total distance, and
  • t is the time taken.

The percentage uncertainty of a fraction is the sum of percentage uncertainties in

  • the numerator, and
  • the denominator.

What are the percentage uncertainties in s and t in this question?

The unit of the absolute uncertainty in s is meters. Thus, convert the unit of s to meters:

s = \rm 42.238\;km = 42.238\times 10^{3}\;m.

\begin{aligned}\displaystyle \text{Percentage Uncertainty in }s &= \frac{\text{Absolute Uncertainty in } s}{\text{Measured Value of }s}\times 100\% \\ &=\rm\frac{29\; m}{42.238\times 10^{3}\;m}\times 100\%\\ &= 0.0687\%\end{aligned}.

The unit of the absolute uncertainty in t is seconds. Convert the unit of t to seconds:

t = \rm 2\times 3600 + 31\times 60 + 46 = 9106\;s

Similarly,

\begin{aligned}\displaystyle \rm \text{Percentage Uncertainty in }t &= \frac{\text{Absolute Uncertainty in }t}{\text{Measured Value of }t}\times 100\% \\ &=\rm\frac{46\; s}{9106\;s}\times 100\%\\ &= 0.0329\%\end{aligned}.

The average speed \bar{v} here is a fraction of s and t. Both s and t come with uncertainty. The percentage uncertainty in \bar{v} will be the sum of percentage uncertainties in s and t. That is:

\text{Percentage Uncertainty in }\bar{v}\\=(\text{Percentage Uncertainty in } s) + (\text{Percentage Uncertainty in } t)\\ = 0.0687\% + 0.0329\%\\ = 0.010\%.

Generally, keep

  • two significant figures for percentage uncertainties that are less than 2%, and
  • one for those that are greater than 2%.

The percentage uncertainty in \bar{v} here is less than 2%. Thus, keep two significant figures. However, keep more significant figures than that in calculations to make sure that the final result is accurate.

3 0
4 years ago
A 4kg watermelon is dropped from a height of 45m. What is the velocity of the watermelon just before it hits the ground?
Makovka662 [10]

Answer:

v=30 m/s

Explanation:

h - height

g - acceleration due to gravity=10

t - time

v- velocity

h =  \frac{1}{2}  \times g \times t {}^{2}

45 = 5t²

t² = 9

t=3 seconds

v=g×t

v=10×3

v=30 m/s

3 0
3 years ago
A 0.119 kg ball is dropped from rest. if the magnitude of the ball's momentum is 0.817 kg·m/s just before it lands on the ground
NemiM [27]
I am not good at math but what grade r u in cause i am in 9th and if u r then i might can help
8 0
3 years ago
PLZ HELP I DON'T UNDERSTAND!! a boy is playing catch with his friend. He throws the ball straight up. When it leaves his hand, t
algol13

Explanation:

The mass of a ball, m = 2 kg

It is traveling with a speed of 10 m/s

The ball's kinetic energy just as it leaves the boy's hand is calculated as follows :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 2\times (10)^2\\\\=100\ J

The ball's kinetic energy just as it leaves the boy's hand is 100 J. The potential energy of the ball when it reaches the highest point is same as the kinetic energy as it leaves the boy's hand.

Hence, the required kinetic and potential energy is 100 J.

6 0
3 years ago
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