Answer:C) car X
Explanation:
Given
All the cars have identical Engine thus Force Produced by car X will be equal to Y and Z
and 
Since Car X is most massive so acceleration associated with it will be minimum
acceleration of car X is minimum thus it will travel farthest
Answer:
1.31498 kg
0.72050 s
0.72050 s
Explanation:
m = Mass of block
g = Acceleration due to gravity = 9.81 m/s²
k = Spring constant = 100 N/M
x = Displacement = 0.129 m
The force balance is
The mass of the block is 1.31498 kg
Time period is given by
The period of oscillations is 0.72050 s
The time period does not depend on the acceleration due to gravity. It varies with the mass and the spring constant.
Hence, the time period would be the same
Answer:
time is 0.5660 s
and time is - 3.62431 s
Explanation:
velocity u = 15 m/s
height s = 10 m
acceleration due to gravity g = –9.8 m/s²
to find out
time
solution
we will apply here distance equation that is
s = ut - 1/2× gt² ...........1
here put all these value and get time t
here s is height and g is -9.8
so
s = ut - 1/2× gt²
10 = 15t - 1/2× (-9.8)t²
10 = 15t + 4.9t²
solve it we get t
t = 0.56630 and -3.62431
so time is 0.5660 s
and time is - 3.62431 s
<span>k = 1.7 x 10^5 kg/s^2
Player mass = 69 kg
Hooke's law states
F = kX
where
F = Force
k = spring constant
X = deflection
So let's solve for k, the substitute the known values and calculate. Don't forget the local gravitational acceleration.
F = kX
F/X = k
115 kg* 9.8 m/s^2 / 0.65 cm
= 115 kg* 9.8 m/s^2 / 0.0065 m
= 1127 kg*m/s^2 / 0.0065 m
= 173384.6154 kg/s^2
Rounding to 2 significant figures gives 1.7 x 10^5 kg/s^2
Since Hooke's law is a linear relationship, we could either use the calculated value of the spring constant along with the local gravitational acceleration, or we can simply take advantage of the ratio. The ratio will be both easier and more accurate. So
X/0.39 cm = 115 kg/0.65 cm
X = 44.85 kg/0.65
X = 69 kg
The player masses 69 kg.</span>
