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Sergio039 [100]
4 years ago
14

What force decreases as air rises that allows it to expand?

Physics
1 answer:
denpristay [2]4 years ago
7 0
Atmospheric pressure falls at greater altitudes because there is less weight of air<span> above the point of observation</span>
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The quantity of heat Q that changes the temperature L1Tof a mass mof a substance isgiven by Q = cmt:T, where c is the specific h
White raven [17]

Answer:

a) Q = 80,000 cal

b) Q = 100,000 cal

c) Q = 540,000 cal

d) Q = 720,000 cal

Explanation:

a)1 kg from 0⁰ Ice to 0⁰ water, the heat produced is latent heat of fusion

Q_{l}  = ML_{f} = 1 * 80

Q_{l} = 80 kCal = 80,000 cal

b) 1 kg of O°C ice water to 1 kg of 100°C boiling water

Specific heat capacity, c =  1000cal/kg.C

Q_{c} = mc \delta T\\Q_{c} = 1 * 1000 * (100 - 0)\\Q_{c} =100000 cal

c) 1 kg of 100°C boiling water to 1 kg of 100°C steam

Latent heat of vaporization is needed for this conversion

Q_{v} = ML_{v} \\L_{v} = 540 kCal/kg\\Q_{v} =1* 540 \\Q_{v} = 540 kCal = 540000 cal

d)  1 kg of O°C ice to 1 kg of 100°C steam.

Q = Q_{L} + Q_{c} + Q_{v}

Q = 80,000 + 100,000 + 540,000

Q = 720,000 cal

7 0
4 years ago
If 400 pa of pressure is applied to an area of 55 m2, which is the resulting force?345 n7.27 n22,000 n
VashaNatasha [74]
The answer should hopefully be: 7.27N
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4 years ago
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An empty capacitor is capable of storing 1.0 × 10-4 J of energy when connected to a certain battery. If the distance between the
dangina [55]

Answer:

Explanation:

Energy stored in a capacitor

= 1/2 C₁V²

capacity of a capacitor

c = εK A / d

k is dielectric and d is distance between plates .

When  the distance between the plates is halved and then filled with a dielectric (κ = 4.3)

capacity becomes 4.3  x 2 times

New capacity

C₂ = 8.6 C₁

Energy of modified capacitor

1/2 C₂ V²= 1/2 x 8.6 c x V²

Energy becomes

8.6 times.

Energy stored = 8.6 x 10⁻⁴ J

3 0
4 years ago
Why does a ship need an anchor
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So there is extra wait that pulls the boat to stop.

Can i get brainliest I need it

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3 years ago
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The image produced by an object is –10.0 cm from a concave mirror that has a focal length of 5.0 cm. The distance of the object
Gennadij [26K]
Given:
Focal length: 5.0 cm
image produced: -10.0 cm

mirror equation:   1/di + 1/do = 1/f

Look for the actual distance of the object from the mirror. Solve for do.

1/do + 1/(-10) = 1/5
1/do = 1/5 + 1/10
1/do = (1/5 * 2/2) + (1/10 * 1/1)
1/do = 2/10 + 1/10
1/do = 3/10
10 = 3do
10/3 = do
3.33 = do

The distance of the object from the mirror, rounded to the nearest centimeter is 3 cm.
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4 years ago
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