A copper block is removed from a 310C oven and dropped into 1.10kg of water at 23.0C. The water quickly reaches 33.0C and then r
1 answer:
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Answer:
The helicopter was 1103.63 meters high when the package was dropped.
Explanation:
We consider positive speed as a downward movement
y: height (m)
t: time (s)
v₀: initial speed (m/s)
Δy = v₀t + gt²
Δy= 15×15 s +
×9.81
×(15 s)²
Δy= 1103.63 m
Answer:
The magnitude of the magnetic field is .
Explanation:
Given that,
Charge,
Speed of the charged particle,
The angle between the velocity of the charge and the field is 56°.
The magnitude of force,
We need to find the magnitude of the magnetic field. When a charged particle moves in the magnetic field, the magnetic force is experienced by it. The force is given by :
B is the magnetic field.
So, the magnitude of the magnetic field is . Hence, this is the required solution.
Answer:
F_B = 6.4*10^-13 N
Explanation:
The magnetic force on the electron, generated by the motion of the electron and the magnetic field is given by:
q: electron charge = 1.6*10^{-19}C
v: speed of the electron = 2.0*10^6 m/s
B: magnitude of the magnetic field = 2T
However, the direction of B and v are perpendicular between them. So, the angle between vectors is 90°. The magnitude of the magnetic force is:
You replace the values of q, v and B in the last equation:
hence, the magnetic force on the electron is 6.4*10^-23 N