Answer:
0.432kg or 432g
Explanation:
Copper block is removed from 310C oven.
Mass of water = 1.10kg
Initial temperature of water (θ1) = 23.0C
Final temperature of water (θ2 ) = 33.0C
Specific heat of copper= 385
Specific heat of water = 4190
Let M (copper) be the mass of copper
The amount of heat lost will be absorbed by water
Q (net) = Q(water) + Q(copper) = 0 …………………(1)
Q = MCθ
For water,
Q(water) = M(water) * C(water) * (θ2-θ1)...........(2)
= 1.1 * 4190 * (33.0 -23.0)
= 1.1 *4190 * 10
= 46090J
For copper,
Q(copper) = M(copper) * C(copper) * (33.0 - 310)...........(3)
from equation 1,
Q(copper) = -Q(water)
M(copper) * C(copper) * (33.0 - 310) = - 46090
M(copper) * 385 * (-277) = -46090
M(copper) * 106645 = -46090
M(copper) = -46090 / -106645
M(copper) = 0.432kg
M(copper) = 432g
The mass of copper =432g
