Answer:
- The system of equations is x + y = 85 and 7/20x+2/5y=31
- To eliminate the x-variable from the equations, you can multiply the equation with the fractions by 20 and multiply the other equation by -7.
- B-She used 60 minutes for calling and 25 minutes for data.
Step-by-step explanation:
It is always a good idea to start by defining variables in such a problem. Here, we can let x represent the number of calling minutes, and y represent the number of data minutes. The the total number of minutes used is ...
x + y = 85
The total of charges is the sum of the products of charge per minute and minutes used:
7/20x + 2/5y = 31.00
We can eliminate the x-variable in these equations by multiplying the first by -7 and the second by 20, then adding the result.
-7(x +y) +20(7/20x +2/5y) = -7(85) +20(31)
-7x -7y +7x +8y = -595 +620 . . . . eliminate parentheses
y = 25 . . . . . . . . simplify
Then the value of x is
x = 85 -y = 85 -25
x = 60
25) -4
26) -8
27) 0
28) -7
29)6
Answer:
A = 0
Step-by-step explanation:
3 times 0 =0
0 + 8 = 8
8 divided by 2 = 4
4 is less than 10
Answer:
42 cups of chips
Step-by-step explanation:
Answer / Step-by-step explanation:
To properly understand the principle behind the solving of this question, it would be necessary to define and go through some basic terms and their definition.
Therefore to start with, a completely randomized single factor is a type of experiment in which One factor of two or more levels has been manipulated. e.g, the experiment may be investigating the effect of different levels of cost, expenditure or different advertisements
Also, it should be noted that in the area of groping of the experiment, At this point, Each group of different level receives one of the a levels of the independent variable with participants being treated identically in every other respect. The two-group experiment considered previously is a special case of this type of design.
Consequentially, the answer to the narrative of the question would then be:
N= 3 factors levels x 5 replicates = 15
Degrees of freedom for the factor: a – 1 = 3 – 1 = 2
Degrees of freedom Total = 15 – 1= 14
Degrees of freedom error = Total – factor = 14 – 2 = 12
Bounds of P-value for F = 2.91 with 2 and 12 degrees of freedom are
= 0.01 < P < 0.05
