Let x be the resistance of the wire with the larger diameter.
x = (0.456 x (0.01)^2)/(0.0401)^2 = 0.0284 ohms
The answer is 0.0284 ohms.
Answer:
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Step-by-step explanation:
Find the nth term of this number sequence.
2 8 14 20 26
Again write the numbers 1 to 5 above the numbers in the sequence, and leave a spare line again.
n 1 2 3 4 5 (1st row)
(2nd row)
2 8 14 20 26 (3rd row)
Since the sequence is going up by 6, write down your multiples of 6 on the 2nd row.
n 1 2 3 4 5 (1st row)
6n 6 12 18 24 30 (2nd row)
2 8 14 20 26 (3rd row)
Now, to get the numbers in the 3rd row from the 2nd row take off 4.
So, to get from the position numbers (n) to the numbers in the sequence you have to times the position numbers by 6 and take off 4.
Therefore, the nth term = 6n – 4
The square of the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two sides.
You can use Pythagoras' Theorem to calculate QR:
a^2 + b^2 = c^2
5^2 + 12^2 = QR^2
25 + 144 = QR^2
169 = QR^2
This means that the square root of 169cm is QR, which is 13cm.
SR is equal to QR, which means that SR is 13cm.
