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2 years ago

What is an equation of the line that is perpendicular to y=−23x+5 and passes through the point (2, 11) ?

Mathematics

2 answers:

hichkok12 [17]2 years ago

5 0

Answer:

The equation would be y = 1/23x - 251/23

Step-by-step explanation:

To start, you need to locate the slope of the first equation. Since the slope is the coefficient of x, we know it to be -23. Now, the perpendicular slope is the opposite and reciprocal of that, which makes the new slope 1/23.

Now that we have this, we can use the point and the slope in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 11 = 1/23(x - 2)

y - 11 = 1/23x - 2/23

y = 1/23x - 251/23

Elina [12.6K]2 years ago

5 0

Answer:

Step-by-step explanation:

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