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SSSSS [86.1K]
3 years ago
10

If you can help me it will mean a lot.

Mathematics
1 answer:
Assoli18 [71]3 years ago
3 0

Answer:

y - -x + 2.

Step-by-step explanation:

The line passes through (0, 2) and 5, 1) so it slope = (1-2) / (5-0)

= -1 and the y-intercept is  at y = 2 so the equation is

y - -x + 2.

You might be interested in
The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity v_0 , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0
3 years ago
HELP PLEASEEEEEEEEEeeeee
maks197457 [2]
Might have to experiment a bit to choose the right answer.

In A, the first term is 456 and the common difference is 10.  Each time we have a new term, the next one is the same except that 10 is added.

Suppose n were 1000.  Then we'd have 456 + (1000)(10) = 10456

In B, the first term is 5 and the common ratio is 3.  From 5 we get 15 by mult. 5 by 3.  Similarly, from 135 we get 405 by mult. 135 by 3.  This is a geom. series with first term 5 and common ratio 3.   a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.

Can you now examine C and D in the same manner, and then choose the greatest final value?  Safe to continue using n = 1000.





3 0
3 years ago
I NEED HELP ASAP THANKSSS<br><br> factor x^2 +9x+20
matrenka [14]

Answer:

(x + 5)(x + 4)

Step-by-step explanation:

x^{2} +9x+20=(x+5)(x+4)

6 0
3 years ago
Read 2 more answers
an internet passcode consists of a digit followed by a letter, followed by another digit. Assuming the digits are 0-9, how many
anyanavicka [17]
There are 10 single-digits (0 through 9) and 26 letters (A through Z)

For the first slot there are 10 choices which represents selecting a single digit
For the second slot there are 26 choices because we choose a single letter here.
Finally there are another 10 choices for the third slot (assuming repeats are allowed)

Multiply the values out: 10*26*10 = 260*10 = 2600

Answer: 2600
8 0
3 years ago
Quick help
11Alexandr11 [23.1K]
Isn’t it because of dilation?
8 0
2 years ago
Read 2 more answers
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