Answer:
The measure of minor arc GFC is 
Step-by-step explanation:
we know that
In a circle the sum of the major arc plus the minor arc is equal to 360 degrees
see the attached figure to better understand the problem
Let
x------> the major arc GEC
y-----> the minor arc GFC
so

we have

substitute in the equation and solve for y


Three hundred and eighty nine thousand , four hundred and fifty - seven.........

Multiply both sides by 7/5.





Equation of circle at center (h,k) is given by

Given that center is at (5,0) that means h=5 and k=0
plug both values into above formula

...(i)
Given that circle passes through point (1,1) so it will satisfy above equation




Now plug this value of r^2 into equation (i)
which best matches with choice C
Hence
is the final answer.