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Temka [501]
3 years ago
12

There are 64 boxes of pencils in a case. each box weighs 2.5 ounces. what is the weight of a case

Mathematics
1 answer:
agasfer [191]3 years ago
4 0
64= 2.5x
64/2.5=
25.6 ounces is the weight of a case
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Help ASAP 20 Points
Licemer1 [7]

Answer:

volume of hemisphere = 452.16 ft³

volume of cylinder = 2260.8 ft³

total volume = 2712.96 ft³

1/3 full = 904.32 ft³

Step-by-step explanation:

volume of hemisphere = 1/2(4/3)(3.14)(6³) = 452.16 ft³

volume of cylinder = (3.14)(6²)(20) = 2260.8 ft³

total volume = 452.16 + 2260.8 = 2712.96 ft³

1/3 full = 2712.96/3 = 904.32 ft³

3 0
3 years ago
What is StartFraction (9.3 times 10 Superscript 34 Baseline) Over (3.1 times 10 Superscript 17 Baseline) EndFraction in scientif
WINSTONCH [101]

Answer:

3x10^17

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Write the equation for a line that passes through the point (-3, 5) and is parallel to
gtnhenbr [62]

Answer:

y=3x+14

Step-by-step explanation:

We can use point-slope formula to find the equation.

y-5=3(x+3)

y-5=3x+9

y=3x+14

5 0
2 years ago
Read 2 more answers
Can someone help with that?<br><br>if x+y=2, calculate: <br>P=4x (x-3)+4y(y-3)+8xy​
olganol [36]

Answer:

Step-by-step explanation:

P = 4x(x - 3) + 4y(y - 3) + 8xy

  = 4x² - 12x + 4y² - 12y + 8xy

  = (4x² + 8xy + 4y²) - (12x + 12y)

 = 4(x² + 2xy + y²) - 12(x + y)

 = 4(x + y)² - 12(x + y)

x+y =2 ⇒ P = 4.2² - 12.2 = 16 - 24 = -8

6 0
3 years ago
2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de
Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


3 0
3 years ago
Read 2 more answers
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