Answer:
Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)
Step-by-step explanation:
<u>Step 1: Factor</u>
p(x) = x^3 - 5x^2 - x + 5
<em>p(x) = (x - 5)(x + 1)(x - 1)</em>
<em />
<em>Yes, the remainder is 0 so, x-5 is a factor of p(x)</em>
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Answer: Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)
Answer:
(-2, 20)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -7x + 6
y = -10x
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [1st Equation]: -10x = -7x + 6
- [Addition Property of Equality] Add 7x on both sides: -3x = 6
- [Division Property of Equality] Divide -3 on both sides: x = -2
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute in <em>x </em>[2nd Equation]: y = -10(-2)
- Multiply: y = 20
_C because multiply 2X times f(x) Kansas X out to make it zero Sony multiply -4 times X it will leave you with a positive four instead since X times X
Answer:0.8
Step-by-step explanation:
it is basically 10 times 8 to the power of -1
