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kotykmax [81]
3 years ago
5

Tom bought 3 packages of Skittles for $1.25 each. How much did he spend?

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
7 0
3.75...hope this helps
DanielleElmas [232]3 years ago
4 0
Hey!


Let's see here. Now, to solve this problem we simply have to multiply the number of packages bought by the cost for each. This will give us the answer.

<em>Created Equation :</em>
3 • 1.25 <span>= ?
</span>
<em>Solution {Created Equation Solved} :</em>
3.75

<em>So, this means that if </em><span><em>Tom bought 3 packages of Skittles for $1.25 each, then he spent a total of</em>  $3.75.

Hope this helps!


- Lindsey Frazier ♥</span>
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Write and solve a real-world problem that represents the following one-variable inequality.
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Hello there! An example problem for this could be:
Emile is looking for a cell-phone plan. His two options are one that costs $40 up front, and costs $0.01 per text, represented by x. The second one is 15 dollars up front and costs $0.06 for each text message. Emile figures that for the first package he has to send 500 texts or more to make it less than the second one. 
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3 years ago
Gravel is being dumped from a conveyor belt at a rate of 15 ft3/min, and its coarseness is such that it forms a pile in the shap
gayaneshka [121]

Answer:

0.13 ft/min

Step-by-step explanation:

We are given that

\frac{dV}{dt}=15ft^3/min

We have to find the increasing rate of change of height of pile  when the pile is 12 ft high.

Let d be the diameter of pile

Height of pile=h

d=h

Radius of pile,r=\frac{d}{2}=\frac{h}{2}

Volume of pile=\frac{1}{3}\pi r^2 h=\frac{1}{12}\pi h^3

\frac{dV}{dt}=\frac{1}{4}\pi h^2\frac{dh}{dt}

h=12 ft

Substitute the values

15=\frac{1}{4}\pi(12)^2\frac{dh}{dt}

\frac{dh}{dt}=\frac{15\times 4}{\pi(12)^2}

\frac{dh}{dt}=0.13ft/min

7 0
3 years ago
what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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Elsa's store purchased a sofa at a wholesale price of $350, and sold it for $630. What is the percent of markup?
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Answer:

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Step-by-step explanation:

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Can someone help me with this ASAP
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Text my number ( 4015166761) i did all of that already im in 7th ill hook u up wit all the answers .
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